i need help asap!!! What is 936.059013 rounded to the nearest tenth? 936.0 936.1 936.05 936.06

Mathematics

2 answers:

kicyunya [14]2 years ago

6 0

i believe 936.06 is the correct anwser

Harrizon [31]2 years ago

3 0

The answer would be 936.1

You might be interested in

Compare using <, >, = 5+(-4)____-4 + (-7)

nikitadnepr [17]

Good morning,

Answer:

Step-by-step explanation:

5+(-4) = 5 - 4 = 1

-4 + (-7) = -(4+7) = -11

since 1 > -11 then 5+(-4) > -4 + (-7)

4 0

3 years ago

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$