Answer:
4 inches
Step-by-step explanation:
of 11 inches of wire costs 44 cents, then 1 inch of wire costs 4 cents because 44 cents ÷ 11 inches = 4 cents per inch. (44 ÷ 11 = 4)
So, if 1 inch is 4 cents, 16 cents is 4 inches because 16 ÷ 4 = 4
The correct answer to this question is Choice D: y = c
This is a horizontal asymptote at y = c. The c is the constant value that is added on to the function. The first part of the equation "y=ab^x" is always going to be a positive number bigger than zero. Therefore, the graph will always be just a little bit bigger than c, it can't equal c.
18. The perimeter is simply √3 + √3 + √3 + √3 or 4√3cm, since the perimeter is just all sides added together. You could add the decimal numbers together using a calculator, which I'm not sure if you're supposed to do in your class.
The area is just width times length, so √3 • √3 = 3cm².
19. The perimeter is 2√5 + 2(9 - √5).
This can also be written as 2√5 + 18 - 2√5, which leaves you with a perimeter of 18ft.
The area would be √5 • (9 - √5), which leaves you with (9√5 - 5)ft².
20. The formula for the perimeter (or circumference) of a circle is π times the diameter of the circle. Using the radius of the circle, 1/π, the diameter is 2/π, so
π • 2/π = 2. The circumference of the circle is 2 inches.
The area of the circle is calculated with the equation πr², so
π(1/π)² = π • 1/(π²) = π/(π²) = π. The area is simply π in².
9 out of 12 = 9/12 which can be simplified to 3/4. So the team wins 3/4 of its games. 3/4 of 64 = 64 divided by 4 = 16. 16 x 3 = 48.
Answer:
a) 
b) 
c) 
But we see that the distribution is defined ust between 49.62 and 50.04
And in order to find this we can use the CDF (Cumulative distribution function) given by:
And if we replace we got:
And makes sense since all the values are between 49.62 and 50.04
Step-by-step explanation:
For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:
Part a
For the uniform distribution the expected value is given by 
where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:
Part b
The variance for an uniform distribution is given by:
And if we replace we got:
Part c
For this case we want to find this probability:
But we see that the distribution is defined ust between 49.62 and 50.04
And in order to find this we can use the CDF (Cumulative distribution function) given by:
And if we replace we got:
And makes sense since all the values are between 49.62 and 50.04
