4. A rock is thrown with a height equation of h = -16t2 + 64t + 5 (where h is the height of the rock in feet at any given time o
f t in seconds). Will it reach a height of 50 feet? Explain your answer.
1 answer:
Answer:
Yes, see below.
Step-by-step explanation:
Convert the equation to vertex form to find the maximum height:
h = -16t2 + 64t + 5
= -16(t^2 - 4t) + 5
= -16 [(t - 2)^2 - 4] + 5
= -16( t - 2)^2 + 64 + 6
= -16(t - 2)^2 + 69.
So the maximum height the rock reaches is 69 feet.
This height is reached at 2 time seconds.
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