I don’t know I just need points lol
Answer:
the answer is two groups. six times two is 12, 12 is one less than 13 but six cannot go into one
Step-by-step explanation:
20fruits=100%
5fruits=?
5x100/20 5fruitsx5%
=24%
Answer:
![Width = 4ft](https://tex.z-dn.net/?f=Width%20%3D%204ft)
![Height = 4ft](https://tex.z-dn.net/?f=Height%20%3D%204ft)
![Length = 8ft](https://tex.z-dn.net/?f=Length%20%3D%208ft)
Step-by-step explanation:
Given
![Volume = 128ft^3](https://tex.z-dn.net/?f=Volume%20%3D%20128ft%5E3)
![L = 2W](https://tex.z-dn.net/?f=L%20%3D%202W)
![Base\ Cost = \$9/ft^2](https://tex.z-dn.net/?f=Base%5C%20Cost%20%3D%20%5C%249%2Fft%5E2)
![Sides\ Cost = \$6/ft^2](https://tex.z-dn.net/?f=Sides%5C%20Cost%20%3D%20%5C%246%2Fft%5E2)
Required
The dimension that minimizes the cost
The volume is:
![Volume = LWH](https://tex.z-dn.net/?f=Volume%20%3D%20LWH)
This gives:
![128 = LWH](https://tex.z-dn.net/?f=128%20%3D%20LWH)
Substitute ![L = 2W](https://tex.z-dn.net/?f=L%20%3D%202W)
![128 = 2W * WH](https://tex.z-dn.net/?f=128%20%3D%202W%20%2A%20WH)
![128 = 2W^2H](https://tex.z-dn.net/?f=128%20%3D%202W%5E2H)
Make H the subject
![H = \frac{128}{2W^2}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B128%7D%7B2W%5E2%7D)
![H = \frac{64}{W^2}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B64%7D%7BW%5E2%7D)
The surface area is:
Area = Area of Bottom + Area of Sides
So, we have:
![A = LW + 2(WH + LH)](https://tex.z-dn.net/?f=A%20%3D%20LW%20%2B%202%28WH%20%2B%20LH%29)
The cost is:
![Cost = 9 * LW + 6 * 2(WH + LH)](https://tex.z-dn.net/?f=Cost%20%3D%209%20%2A%20LW%20%2B%206%20%2A%202%28WH%20%2B%20LH%29)
![Cost = 9 * LW + 12(WH + LH)](https://tex.z-dn.net/?f=Cost%20%3D%209%20%2A%20LW%20%2B%2012%28WH%20%2B%20LH%29)
![Cost = 9 * LW + 12H(W + L)](https://tex.z-dn.net/?f=Cost%20%3D%209%20%2A%20LW%20%2B%2012H%28W%20%2B%20L%29)
Substitute:
and ![L = 2W](https://tex.z-dn.net/?f=L%20%3D%202W)
![Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)](https://tex.z-dn.net/?f=Cost%20%3D9%2A2W%2AW%20%2B%2012%20%2A%20%5Cfrac%7B64%7D%7BW%5E2%7D%28W%20%2B%202W%29)
![Cost =18W^2 + \frac{768}{W^2}*3W](https://tex.z-dn.net/?f=Cost%20%3D18W%5E2%20%2B%20%20%5Cfrac%7B768%7D%7BW%5E2%7D%2A3W)
![Cost =18W^2 + \frac{2304}{W}](https://tex.z-dn.net/?f=Cost%20%3D18W%5E2%20%2B%20%20%5Cfrac%7B2304%7D%7BW%7D)
To minimize the cost, we differentiate
![C' =2*18W + -1 * 2304W^{-2}](https://tex.z-dn.net/?f=C%27%20%3D2%2A18W%20%2B%20%20-1%20%2A%202304W%5E%7B-2%7D)
Then set to 0
![2*18W + -1 * 2304W^{-2} =0](https://tex.z-dn.net/?f=2%2A18W%20%2B%20%20-1%20%2A%202304W%5E%7B-2%7D%20%3D0)
![36W - 2304W^{-2} =0](https://tex.z-dn.net/?f=36W%20-%202304W%5E%7B-2%7D%20%3D0)
Rewrite as:
![36W = 2304W^{-2}](https://tex.z-dn.net/?f=36W%20%3D%202304W%5E%7B-2%7D)
Divide both sides by W
![36 = 2304W^{-3}](https://tex.z-dn.net/?f=36%20%3D%202304W%5E%7B-3%7D)
Rewrite as:
![36 = \frac{2304}{W^3}](https://tex.z-dn.net/?f=36%20%3D%20%5Cfrac%7B2304%7D%7BW%5E3%7D)
Solve for ![W^3](https://tex.z-dn.net/?f=W%5E3)
![W^3 = \frac{2304}{36}](https://tex.z-dn.net/?f=W%5E3%20%3D%20%5Cfrac%7B2304%7D%7B36%7D)
![W^3 = 64](https://tex.z-dn.net/?f=W%5E3%20%3D%2064)
Take cube roots
![W = 4](https://tex.z-dn.net/?f=W%20%3D%204)
Recall that:
![L = 2W](https://tex.z-dn.net/?f=L%20%3D%202W)
![L = 2 * 4](https://tex.z-dn.net/?f=L%20%3D%202%20%2A%204)
![L = 8](https://tex.z-dn.net/?f=L%20%3D%208)
![H = \frac{64}{W^2}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B64%7D%7BW%5E2%7D)
![H = \frac{64}{4^2}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B64%7D%7B4%5E2%7D)
![H = \frac{64}{16}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B64%7D%7B16%7D)
![H = 4](https://tex.z-dn.net/?f=H%20%3D%204)
Hence, the dimension that minimizes the cost is:
![Width = 4ft](https://tex.z-dn.net/?f=Width%20%3D%204ft)
![Height = 4ft](https://tex.z-dn.net/?f=Height%20%3D%204ft)
![Length = 8ft](https://tex.z-dn.net/?f=Length%20%3D%208ft)
Answer:
19 m
Step-by-step explanation:
base=x
leg=3x-2
3x-2+3x-2+x=45
7x-4=45
7x=49
x=7
leg=3x+2=3(7)-2=19