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4 years ago

Two thirds of a full turn

Mathematics

1 answer:

Nady [450]4 years ago

3 0

A full turn is also a 360 degrees turn.

Two thirds is $\frac { 2 }{ 3 }$

To find two thirds of 360 we'll multiply it by $\frac { 2 }{ 3 }$

$360\cdot \frac { 2 }{ 3 } \quad =\quad \frac { 360\cdot 2 }{ 3 } \quad =\quad \frac { 720 }{ 3 } \quad =\quad 240$

Two thirds of a full turn ( ${ 360 }^{ o }$ ) is:

$\boxed { { 240 }^{ o } }$ degrees.

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Determine whether these statements are true or false. a) ∅ ∈ {∅} b) ∅ ∈ {∅,{∅}} c) {∅} ∈ {∅} d) {∅} ∈ {{∅}} e) {∅} ⊂ {∅,{∅}} f )

Pavel [41]

Answer:

a) ∅ ∈ {∅} TRUE

b) ∅ ∈ {∅,{∅}} TRUE

c) {∅} ∈ {∅} FALSE

d) {∅} ∈ {{∅}} TRUE

e) {∅} ⊂ {∅,{∅}} TRUE

f ) {{∅}} ⊂ {∅,{∅}} TRUE

g) {{∅}} ⊂ {{∅},{∅}}FALSE

Step-by-step explanation:

To assess whether these statements are true or false, first observe the symbol:

"∈" means that element, as it is and as it is, belongs to the set. To belong to the set it must be within the symbols "{}"

On the other hand, the symbol "⊂" means "subset", that is, it is a subset that is included in the main set.

So:

c) is false because "{∅}" is not included in the set

g) is false because " {{∅}}" is not included in the set

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3 years ago

7,,,,,,,,,,,,,,,,,,,,please help

Goryan [66]

Answer:

Step-by-step explanation:

The given expression is

$\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}$

Recall and use

$a^m\times a^n=a^{m+n}$

$\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}$

$\frac{2^{-\frac{13}{2}}}{ 2^{-\frac{13}{2}}}$

Same bases are dividing, so we write one base and subtract the exponent.

$2^{-\frac{13}{2}+\frac{13}{2}}$

$2^0=1$

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3 years ago

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statuscvo [17]

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Frank invest $500 at a simple interest rate of 3%. How much interest will earn after 5 years

svet-max [94.6K]

He will earn 75 dollars

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4 years ago

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The graph of y= - 1/2x+2 is positive over the interval (4, infinity) and negative over the interval (-infinity, 4) .What happens

vichka [17]

The graph of y=ax+b, where a≠0, is always a line:

i) increasing if a>0
ii) decreasing if a<0

Consider the decreasing case.

The line is above the x-axis, that is positive but decreasing. At 1 single point it cuts the x-axis, so x=0, and then it continues decreasing below the x-axis.

Back to our problem:

The graph of y=-1/2 x +2 is a decreasing line.,

so it CANNOT be
"positive over the interval (4, infinity) and negative over the interval (-infinity, 4)"

it is

"<span>negative over the interval (4, infinity) and positive over the interval (-infinity, 4)</span>"

the graph is "<span>positive over the interval (-infinity, 4)</span>", it means that the line is decreasing but above the x-axis until 4, (4 not included).

then, "negative over the interval (4, infinity)", which means that the line is now decreasing below the x-axis.

when x=4, the line cuts the x-axis.

check the graph of the line generated using desmos.com

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4 years ago