An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides
assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent
ok, solve initial
x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation
-x-y=-1
<u>x-3y=9 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=1
x-2=1
add 2
x=3
x=3
y=-2
(3,-2)
if we test it in other one
2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep
2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep
solution is (3,-2)
Answer:

Step-by-step explanation:
The complete question is shown in the attachment.
The length of the rectangle is x + 12. The width of the rectangle is x + 3.
Recall that area of a rectangle is 
In terms of x, the area is 
Recall the distributive property of real numbers: 
We apply this property to get:

We expand again to get:

We now simplify to obtain:

The area of the rectangle is 
Answer:
true
Step-by-step explanation:
Answer:
Graph the inequality by finding the boundary line, then shading the appropriate area.
y
<
3
+ x/2
Step-by-step explanation: