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sasho [114]
3 years ago
10

What is the domain of the function shown in the

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

{x | x = -5, -3, 1, 2, 6}

Step-by-step explanation:

In a function, the domain values are all the possible values of input in a function. In order words, they are the x-values in a function, which are also referred to as independent variable.

In the mapping of the function above, all input values make up the domain of the function.

Thus, the domain is:

{x | x = -5, -3, 1, 2, 6}

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B

Step-by-step explanation:

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I need help with this please
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3) 0 ≤ y ≤ 100
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What is the end behavior of the graph of
lutik1710 [3]

The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.

<h3>What is the end behavior about?</h3>

The end behavior of a function f tells us that the way that the graph function behaves at the "ends" of the x-axis.

Note that the end behavior of a function tells the trend of the graph and in this graph, f(x) -----> +∞ as x----> -∞  (as the value of x decreases the value of f(x) increases) and  f(x) -----> -∞ as x----> +∞ (as the value of x increases the value of f(x) decreases).

Therefore, The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.

See full question below

What is the end behavior of the graph of f(x) = -0.25x2 - 2x + 1?

A) As x increases, f(x) increases. As x decreases, f(x) decreases.

B) As x increases, f(x) decreases. As x decreases, f(x) decreases.

C) As x increases, f(x) increases. As x decreases, f(x) increases.

D) As x increases, f(x) decreases. As x decreases, f(x) increases

Learn more about end behavior from

brainly.com/question/1365136

#SPJ1

5 0
2 years ago
Pls help me solve for x in 2/3=x/4+x/3
Firlakuza [10]

Answer:

x=8/7

Step-by-step explanation:

2/3=x/4+x/3

3x/12+4x/12=8/12

7x/12=8/12

x=(8/12)/(7/12)

x=(8/12)(12/7)

x=8/7

7 0
3 years ago
PLSSSSSSSSSSSSS HELp VERY URGENT The graph of F(x), shown below, resembles the graph of G(x) = x^2, but it has been stretched so
netineya [11]

Answer:

Option B

Step-by-step explanation:

Function 'g' is,

g(x) = x²

Since, leading coefficient of this function is positive, parabola is opening upwards.

From the graph attached,

Function 'f' is opening upwards leading coefficient of the function will be positive.

Since, the graph of function 'f' is vertically stretched, equation will be in the form of f(x) = kx²

Here, k > 1

Since, function 'f' is formed by shifting the graph of function 'g' by 1 unit upwards,

f(x) = g(x) + 1

Combining all these properties, equation of the function 'f' should be,

f(x) = 4x² + 1

Option B will be the correct option.

3 0
3 years ago
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