Answer:
1. x = 8
2. x = 12
3. x = 11
4. x = 6
Step-by-step explanation:
1.
102 + 102 = 204
360 - 204 = 156
156 / 2 = 78
78 = 10x - 2
78 + 2 = 10x
80 = 10x
80 / 10 = x
x = 8
2.
81 = 7x - 3
81 + 3 = 7x
84 = 7x
84 / 7 = x
x = 12
3.
77 = 6x + 11
77 - 11 = 6x
66 = 6x
66 / 6 = x
x = 11
4.
115 + 115 = 230
360 - 230 = 130
130 / 2 = 65
65 = 8x + 17
65 - 17 = 8x
48 = 8x
48 / 8 = x
x = 6
Answer:
32.6
Step-by-step explanation:
when you plug in for s and r you will get 66-33.4 since 5.5 multiped by 12 is 66 and 8.35 multiplied by 4 is 33.4 .
then you subtract them and that's how you'll get your answer
The equation for a circle is (x - h)^2 + (y - k)^2 = r^2
where (h, k) is the center and r is the radius
(x + 8)^2 + (y + 9)^2 = 169
Since the equation is -h and -k, I will rewrite in terms of -h and -k.
(x - -8)^2 + (y - -9)^2 = 13^2
The center is (-8, -9) and the radius = 13
Let me know if you need me to explain further.
Ok so there are 52 cards in a deck if you take all the cards that have the number 6 which is only 4 cards so 52-4 = 48 cards without any 6 so the ratio is 48/52
chances.
If you're trying to take any card that is greater than 6 its a little more complex there is T,2,3,4,5,6,7,8,9,10,B,Q,K so you have to tack away 6,7,8,9,10,B,Q,K from 4 rows so 8 x 4 =32 cards 52-32= 20 so the probability of not having any cards greater than 6 is 20/52
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
