Answer:
49
Step-by-step explanation:
∆ABC~ ∆XYZ
AB= 11 that is half of XY = 22
therefore XZ/2 = AC (base) = 32/2 = 16
and YZ /2 = BC(hypotenuse) = 44/2 = 22
(a= 11, b= 16, c= 22)
perimeter of a triangle
P = a+b+c
P= 11+16+22= 49
18 |16 | 13 | 10 | 9.5 | 8.5 | 7.5 | 6
9.75 is the FINAL answer
Step-by-step explanation:
I will solve your system by substitution.
(You can also solve this system by elimination.)
4x+y=17;4x−3y=−3
Step: Solve4x+y=17for y:
4x+y+−4x=17+−4x(Add -4x to both sides)
y=−4x+17
Step: Substitute−4x+17foryin4x−3y=−3:
4x−3y=−3
4x−3(−4x+17)=−3
16x−51=−3(Simplify both sides of the equation)
16x−51+51=−3+51(Add 51 to both sides)
16x=48
16/x = 48/16
(Divide both sides by 16)
x=3
Step: Substitute 3 for x in y=−4x+17:
y=−4x+17
y=(−4)(3)+17
y=5(Simplify both sides of the equation)
Answer:
x=3 and y=5
