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3 years ago

Six light bulbs are connected in series with a 9.0 volt battery. What is the voltage across each bulb?

1 answer:

5 0

Voltage adds in a series and the amount of voltage dropped due to each resistor in a circuit (the light bulbs are resistors) depends on the resistance of each.

Assuming equal resistance of each light bulb, the voltage dropped on each is equal and should add up to 9V (Kirchoff's Rules).

So 9V/6 = 1.5V per light bulb.

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6- A metal block measures 10 cm x 2 cm x 2 cm. what is its volume? how many blocks each

zalisa [80]

You need 5 blocks of the smaller object to contain the same amount of volume of the bigger object

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4 years ago

1.60 kg frictionless block is attached to an ideal spring with force constant 315 N/m . Initially the spring is neither stretche

Tatiana [17]

Answer:

(a). The amplitude of the motion is 0.926 m.

(b). The block’s maximum acceleration is 182.31 m/s².

(c). The maximum force the spring exerts on the block is 291.69 N.

Explanation:

Given that,

Mass of block =1.60 kg

Force constant = 315 N/m

Speed = 13.0 m/s

(a). We need to calculate the amplitude of the motion

Using conservation of energy

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2$

$A^2=\dfrac{mv^2}{k}$

Put the value into the relation

$A^2=\dfrac{1.60\times13.0^2}{315}$

$A=\sqrt{0.858}$

$A=0.926\ m$

(b). We need to calculate the block’s maximum acceleration

Using formula of acceleration

$a=A\omega^2$

$a=A\times\dfrac{k}{m}$

Put the value into the formula

$a=0.926\times\dfrac{315}{1.60}$

$a=182.31\ m/s^2$

(c). We need to calculate the maximum force the spring exerts on the block

Using formula of force

$F=ma$

Put the value into the formula

$F= 1.60\times182.31$

$F=291.69\ N$

Hence, (a). The amplitude of the motion is 0.926 m.

(b). The block’s maximum acceleration is 182.31 m/s².

(c). The maximum force the spring exerts on the block is 291.69 N.

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3 years ago

Which of the Jovian planets have rings?

fenix001 [56]

All of the four have rings, but if i'm not mistaken Saturn is the only visible ring.

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3 years ago

Read 2 more answers

A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du

Lana71 [14]

Answer:

$a_E=\dfrac{Gm}{r^2}$

Explanation:

$M_E$ = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of person

The force on the person will balance the gravitational force

$M_Ea_E=\dfrac{GmM_E}{r^2}\\\Rightarrow a_E=\dfrac{Gm}{r^2}$

The acceleration that the Earth will feel is $a_E=\dfrac{Gm}{r^2}$

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3 years ago

How do the sizes of the inner planets (from the sun to the asteroid belt) compare to the sizes of the outer planets?

Oxana [17]

Answer:

The smaller, inner planets include Mercury, Venus, Earth, and Mars. The inner planets are rocky and have diameters of less than 13,000 kilometers. The outer planets include Jupiter, Saturn, Uranus, and Neptune. The outer planets are called gas giants and have a diameter of greater than 48,000 kilometers.

Explanation:

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3 years ago

Six light bulbs are connected in series with a 9.0­ volt battery. What is the voltage across each bulb?

Six light bulbs are connected in series with a 9.0 volt battery. What is the voltage across each bulb?