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AnnZ [28]
3 years ago
9

Six light bulbs are connected in series with a 9.0­ volt battery. What is the voltage across each bulb?

Physics
1 answer:
Anestetic [448]3 years ago
5 0
Voltage adds in a series and the amount of voltage dropped due to each resistor in a circuit (the light bulbs are resistors) depends on the resistance of each.

Assuming equal resistance of each light bulb, the voltage dropped on each is equal and should add up to 9V (Kirchoff's Rules).

So 9V/6 = 1.5V per light bulb.
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A uniform line charge of density λ lies on the x axis between x = 0 and x = L. Its total charge is 7 nC. The electric field at x
DedPeter [7]

Answer:

The electric field at x = 3L is 166.67 N/C

Solution:

As per the question:

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Coulomb constant, K = 8.99\times 10^{9} N.m^{2}/C^{2}

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Integrating both the sides from x = L to x = 2L

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\vec{E_{2L}} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{2L}] = \frac{63}{L^{2}}

Similarly,

For the field in between the range 2L< x < 3L:

\int_{0}^{E}d\vec{E} = K\lambda \int_{2L}^{3L}\frac{1}{x^{2}}dx

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Now,

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Then at x = 3L:

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4 0
4 years ago
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