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adelina 88 [10]

3 years ago

12

A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du

e to the person's gravitational pull?

1 answer:

Lana71 [14]3 years ago

7 0

Answer:

$a_E=\dfrac{Gm}{r^2}$

Explanation:

$M_E$ = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of person

The force on the person will balance the gravitational force

$M_Ea_E=\dfrac{GmM_E}{r^2}\\\Rightarrow a_E=\dfrac{Gm}{r^2}$

The acceleration that the Earth will feel is $a_E=\dfrac{Gm}{r^2}$

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Centripetal acceleration of car is given by formula

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Part b)

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Part c)

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$a_y = -0.98 m/s^2$

Part d)

At position B we have

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Part e)

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$a_y = 2.01 m/s^2$

6 0

3 years ago

In an attempt to escape his island, Gilligan builds a raft and sets to sea. The wind shifts a great deal during the day, and he

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Answer:8.28 km

Explanation:

Given

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After that it drifted along east direction 5.1 km

$r_{23}=5.1 i$

After that it drifts $55^{\circ}$ 7.2 km

$r_{34}=-7.2cos55 i-7.2sin55 j$

After that it drifts $5^{\circ}$ 2.8 km

$r_{54}=-2.8cos5 i+2.8sin5 j$

$r_{5O}$ = $\left [ 2.5cos45+4.7cos60+5.1-7.2cos55-2.8cos5\right ]\hat{i}$ + $\left [ 2.5sin45-4.7sin60-7.2sin55+2.8sin5\right ]\hat{j}$

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$tan\theta =\frac{7.95}{2.299}=3.4580$

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What will happen to a periodic wave acted upon an external damping force?

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Oxana [17]

Answer:

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HOPE THIS HELPS!!

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