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adelina 88 [10]
3 years ago
12

A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du

e to the person's gravitational pull?
Physics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

a_E=\dfrac{Gm}{r^2}

Explanation:

M_E = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of person

The force on the person will balance the gravitational force

M_Ea_E=\dfrac{GmM_E}{r^2}\\\Rightarrow a_E=\dfrac{Gm}{r^2}

The acceleration that the Earth will feel is a_E=\dfrac{Gm}{r^2}

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