consider the motion of the mass parallel to the incline
v₀ = initial velocity at the bottom of incline = 0 m/s
v = final velocity at the top of incline = 8.00 m/s
a = acceleration
d = displacement = L = length of incline = 15 m
using the equation
v² = v²₀ + 2 a d
8² = 0² + 2 a (15)
64 = 30 a
a = 64/30
a = 2.13 m/s²
F = applied force
from the force diagram, perpendicular to incline , force equation is given as
N = mg Cos30
μ = Coefficient of friction = 0.426
frictional force acting on the mass is given as
f = μ N
f = μ mg Cos30
parallel to incline , force equation is given as
F - f - mg Sin30 = ma
F - μ mg Cos30 - mg Sin30 = ma
inserting the values
F - (0.426 x 40 x 9.8) Cos30 - (40 x 9.8) Sin30 = 40 (2.13)
F = 425.82 N
Answer:
The answer is below
Explanation:
Volt in physics is a term that is used to describe the unit of both electrical potential difference and electromotive force. In other words, it is a unit of measuring the voltage between two points. It is represented as "V".
The formula for Voltage is V=IR
Where V= Voltage, I = Current and R = Resistance.
Answer:
a = 85.3×10⁶ m/s²
Explanation:
Please see the attachment below.
Answer:
v = 1.69 m/s
Explanation:
Given that,
Displacement of the student is 304 m due North and it takes 180 s.
We need to find the student's average velocity. Using formula of velocity.
Velocity = displacement/time
Hence, the student's average velocity is 1.69 m/s.
Speed = (distance covered) / (time to cover the distance)..
From the ground to the highest point,
the rocket's AVERAGE speed is
(86 m) / (3.7 sec) = 23.2 m/s (rounded) .
