Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
Answer:
hey iif ram hari n shyam invest then the ratio shall be like x:y:z but the qstn isnot . ram:hari:shyam =? it can't be 4:5 only it might be 4:5:?
Answer:
107 degrees
Step-by-step explanation:
For an inscribed quadrilateral, the opposite angles are supplementary. Thus, B+D = 180 and you can solve for x.
3x+9+2x-4 = 180
5x = 175
x = 35
Next, plug the x value into angle A.
2(35) + 3 = 73
Angle C is the supplement of this which is 180-73 = 107
Answer:
I think it will be less than 69 because the tozal mean is 41 while of A is 69 mean the values has decreased
