Answer:
15.98 dollars
Step-by-step explanation:
its really easy
we need to subtract the total amount that she has spent from the total amount that she had in her purse
the total amount in Megan's purse=$45.12
total amount that Megan spent=$7.89+$21.25 =$29.14
now,
the exact amount that Megan has left = $45.12-$29.14=$15.98
Answer:
Solution :
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Two angles are said to be a pair of
adjacent angles if they have a common
arm and lie on the either sides of the
common arm .
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Now ,
i ) a , b are a pair of adjecent angles .
ii ) c , d are pair of adjecent angles.
iii ) e, f are not adjecent angles .
Step-by-step explanation:
Answer: a²+b² = -99/2
Step-by-step explanation:
Since we are given two equations, this equations will be solved simultaneously to get a² and b²
a³ - 3ab² = 47 ... 1
b³ - 3a² b = 52... 2
From 1, a(a² - 3b²) = 47...3
From 2, b(b² - 3a²) = 52... 4
Adding 3 and 4, we have;
a²+b²-3b²-3a² = 99 (note that a and b will no longer be part of the equations as they have been factored out)
a²+b²-(3b²+3a²) = 99
(a²+b²) -3(b²+a²)= 99
Taking the difference we have
- 2(a²+b²) = 99
a²+b² = -99/2
Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Answer:
[12, 15]
Step-by-step explanation:
{6x + 5y = 147
{8x + 4y = 156
-¾[8x + 4y = 156]
{6x + 5y = 147
{-6x - 3y = -117 ← New Equation
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2y = 30
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2 2
y = 15 [Plug this back into both equations to get the x-coordinate of 12]; 12 = x
So, using the Elimination Method, what I did here was took the bottom equation and multiplied it by -¾, turning 8x to -6x, canceling out all <em>x-terms</em><em>.</em><em> </em>It does not matter which variable you choose to eliminate, as long as you know what you are doing.
I am joyous to assist you anytime.
