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nordsb [41]
3 years ago
5

D) Use your knowledge of scale drawings and image sizes to fill in the missing

Mathematics
2 answers:
astraxan [27]3 years ago
7 0

Answer:

  Your table is filled in below.

Step-by-step explanation:

The scale factor is the ratio of image size to original size. In part (d), the image height is "blocks" while the original height is "feet". So, the units of the scale factor are "blocks/ft".

Sometimes a scale factor has units, like this, and sometimes it is expressed as a pure number. A map scale factor might be the pure number ratio 1 : 62500, or it could also be expressed with units as 1 in : 1 mile.*

__

* actually, these are slightly different scales. 1:62500 is about 0.98643 inches per mile.

kolbaska11 [484]3 years ago
4 0
I know you can figure it out!! you got this
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For the data set below, which of the following measures is greatest? (20, 25, 30, 31, 32, 45, 45, 80). I will give 28 points!
shutvik [7]

Answer:

D.Mean

Step-by-step explanation:

3 0
3 years ago
Right answer gets brainlist
Vladimir [108]

105 i think nvm not corrupted picture

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3 years ago
For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
PLZZZZZZZZ HELP ME I WILL GIVE BRAINLIEST TO THE FASTEST AND MOST ACCURATE
Triss [41]

Answer:

10/1 +54/-6

Step-by-step explanation:

Is this the answer?

4 0
3 years ago
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a lighthouse casts a 128 footshadow a nearby lampost that measures 5 feet 3inches cast an 8 Foot Shadow
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5 times 3 times 8 is the correct answer, because it's like finding the volume.<span />
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