Answer:
Step-by-step explanation:
Count pairs (a, b) whose sum of squares is N (a^2 + b^2 = N)
Given a number N, the task is to count all ‘a’ and ‘b’ that satisfy the condition a^2 + b^2 = N.
Note:- (a, b) and (b, a) are to be considered as two different pairs and (a, a) is also valid and to be considered only one time.
Examples:
Input: N = 10
Output: 2
1^2 + 3^2 = 9
3^2 + 1^2 = 9
Input: N = 8
Output: 1
2^2 + 2^2 = 8
Answer:
- To a whole number: Add the numbers in the ratio together
- To a fraction: Each number in the ratio would become a numerator in a fraction
I hope this helps!
Credit goes to: calculatorsoup.com
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
<span>The answer to this question is the attached image below: It is the given dominoes in each number that matches to the same number of dominoes that former options has to the latter choices. As shows the solution is given below as to clearly show the equation which is designated to the desired domino.</span>
-4.75= z/2
Multiply both sides by 2
-4.75(2)= z/2(2)
Cross out 2 and 2, divide by 1 and becomes z
z=-9.5
Answer: z= -9.5
