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2 years ago

A(n-3)+8=bn solve for n

Mathematics

2 answers:

Naya [18.7K]2 years ago

8 0

Answer:

The value of the equation for n is $n=\frac{-3A+8}{b-A}$ .

Step-by-step explanation:

Consider the provided equation.

$A(n-3)+8=bn$

We need to solve the equation for n.

Open the parentheses as shown:

$An-3A+8=bn$

Subtract both the side by An.

$An-An-3A+8=bn-An$

$-3A+8=bn-An$

Take n common from right side.

$-3A+8=n(b-A)$

Divide both the sides by b-A.

$\frac{-3A+8}{b-A}=\frac{n(b-A)}{b-A}$

$n=\frac{-3A+8}{b-A}$

Hence, the value of the equation for n is $n=\frac{-3A+8}{b-A}$ .

Lelu [443]2 years ago

6 0

I am pretty sure this is right

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