1*2*3*4+1=25=5^2 2*3*4*5+1=121=1^2 3*4*5*6+1=361=19^2
<span>This question can not be answered because the horizontal distance covered is not specified.</span>
Step-by-step explanation:
2( l + w ) = perimeter of triangle
P = 2( 10+8 )
p= 2(18)
p= 36cm
Circle = pie (r) + d. recall d = 2r
P= 3.142 (4) + 8
P= 20.57~
so therefore= , 36 + 2(20.57)= 77.14cm ~ to the nearest tenths
3 km north.
the east and west cancel out and the 5 north being greater than the two south leave you to only have to subtract the 2 south from the 5 north
Answer:
y = 4 sin(2π/11 x) + 2
Step-by-step explanation:
y = A sin(2π/T x + B) + C
where A is the amplitude,
T is the period,
B is the phase shift,
and C is the midline.
A = 4, T = 11, and C = 2. We'll assume B = 0.
y = 4 sin(2π/11 x) + 2
