The picture would change the distance from the bridge, the ground, and the jumper.
Let's start by solving the first equation.
a) -3 = 7 + 2t/3
To begin simplifying this equation, we should multiply both sides by 3 to get rid of the denominator on the right side of the equation.
-9 = 7 + 2t
Next, we should subtract 7 from both sides to cancel out the 7 on the right side.
-16 = 2t
Finally, we should divide both sides by 2.
t= -8
Now let's move on to the next equation.
b) 4(5x-2) = 7(2x+3)
Let's use the distributive property to get rid of the parentheses and their coefficients.
20x-8 = 14x + 21
Now, lets subtract 14x from both sides of the equation.
6x - 8 = 21
Next, let's add 8 to both sides of the equation.
6x = 29
And divide both sides by the coefficient of x, which is 6.
x = 29/6 or 4 5/6
Now for the last equation.
C) 2x - 6 = 20 - 2.5x
First, we should add 2.5x to both sides to cancel out the -2.5x on the right side of the equation.
4.5x - 6 = 20
Now, let's add 6 to both sides to get the variable term alone.
4.5x = 26
Finally, we should divide both sides by 4.5 to get x by itself.
x = 5 7/9
Hope this helps! :)
12/9 is bigger. It’s 1.333~
Answer
y=1/2x-5
Step-by-step explanation:
any line with a 1/2 must be parallel also it cannot be the same line or they wont be parallel
Answer:
Correct choice is A
Step-by-step explanation:
If a function has an inverse, then there is at most one x-value for each y-value.
The tangent function is periodic with period
Hence, at each value for which
is defined,
for each integer n. Therefore, the function
does not have an inverse. Since tangent is not a one-to-one function, the domain must be limited. From examining the graph of the tangent function, we see that in each interval of the form

where k is an integer, the tangent function assumes every value in its range. Moreover, in each such interval, each y-value is achieved exactly once. Hence, we can create an invertible function by restricting the domain tangent function to one such interval. Such interval is an interval between two consecutive vertical asymptotes
and 