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WARRIOR [948]
3 years ago
8

What number is 150 more than the product of 5 and 4892

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0
24,610. All you have to do is multiply 5 and 4,852 and add 150.
ANTONII [103]3 years ago
3 0
4892*5+150=24610 so 24610 would be the answer. 
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1377/8 in simplest form<br><br> Thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
nlexa [21]
To convert a fraction to simplest form we need to find the greatest common factor. 

The fraction can not be simplified because it is already in simplest form but we can change it to a mixed fraction. 

         Steps to solve 

<span>1) Set up the long division.
</span>
<span>2) Calculate 13 ÷ 8, which is 1 with a remainder of 5.
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3) Bring down 7, so that 57 is large enough to be divided by 8.

4) Calculate 57 ÷ 8, which is 7 with a remainder of 1.

<span>5) Bring down 7, so that 17 is large enough to be divided by 8.
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<span>6) Calculate 17 ÷ 8, which is 2 with a remainder of 1.
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<span>7) Therefore, 1377 ÷ 8 = 172 with a remainder of 1.
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<span>Express as a mixed fraction = </span>172 \dfrac{1}{8}


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3 years ago
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bonufazy [111]

Answer:

0 is the answer.

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0=0

3 0
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Determine the value of sin○​
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3 0
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Read 2 more answers
1. Si μ es un ángulo agudo y cot μ = , ¿cuáles son los valores de todas las funciones trigonométricas de μ?
Scilla [17]

Answer:

Funciones trigonométricas de μ

sen (μ) = b/ √(a^2+ b^2)

cos (μ) = a/ √(a^2+ b^2)

tan (μ)  = b/ a

cot (μ)  = a/ b

sec (μ) =  √(a^2+ b^2) / a

csc (μ) =   √(a^2+ b^2) /b

Step-by-step explanation:

Ya que no proportionaste el valor de cot μ podemos suponer un valor = a/b para que tengas una respuesta general y reemplaces el valor de a y b de acuerdo con tu caso.

cot (μ) = a/b

_______________________________

Funciones trigonométricas

sen (μ) = cateto opuesto/ hipotenusa

cos (μ) = cateto adyacente/ hipotenusa

tan (μ)  = cateto opuesto/ cateto adyacente

cot (μ)  = cateto adyacente/ cateto opuesto

sec (μ) =  hipotenusa / cateto adyacente

csc (μ) =   hipotenusa /cateto opuesto

cot (μ)  = cateto adyacente/ cateto opuesto = cot (μ)  = a/ b

Por lo tanto:

Cateto adyacente = a

Cateto opuesto = b

Hipotenusa

H^2 = Cateto adyacente^2 + Cateto opuesto^2

H= √(a^2+ b^2)

Reemplaznado los valores de los catetos y la hipotenusa se obteienen los valores de las funciones trigonométricas de μ.

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Point slope for will always be y=mx+b
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