3 years ago

What is the next number in sequence -7, -2, 3, 8

Mathematics

2 answers:

olga55 [171]3 years ago

6 0

Ur next number would be 13 as u'r adding 5 each time

Luden [163]3 years ago

4 0

You are adding five to the previous number every time. -7 + 5 = -2 and so on. So the answer would be 13

You might be interested in

Babatunde draws a drinking glass on graph paper using the scale shown below. The glass has a length of 888 units in the drawing.

Helen [10]

Answer: Is there a picture? It would really help me understand you question if you added a picture.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The expression x3 – 64 can be written as (x)3 – (4)3. What is the factorization of x3 – 64?

Sergio [31]

By factoring x^3-64 put you should get the second option as your answer

(x-4)(x^2+4x+16)

5 0

3 years ago

Read 2 more answers

Complete the sentence to make it a true statement. 60 is 1/100 of

Over [174]

Answer:

6000

Step-by-step explanation:

If it is one hundredth than multiply by 100 to get 6000

3 0

2 years ago

A rectangle has a length of 12.6 m and a width of 6.3 m. A similar rectangle has a width of 2.1 m. What is the length of the sim

Oxana [17]

Step-by-step explanation:

Please see the photo for the method

5 0

3 years ago

A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbit

Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

$R(1) = 100(\frac{2}{5}.1 )$

$R(1) = 100(\frac{2}{5} )$

R(2) = $100(\frac{2}{5}.2 )$

$R(2) = 100(\frac{4}{5} )$

$\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )$

$\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]$

$\Delta R=$ 40

Difference of rabbits between first and second months is 40.

b. R(0) = 100( $\frac{2}{5} .0$ )

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = $100(\frac{2}{5}.10 )$

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

$500=100(\frac{2}{5}.t )$

$\frac{500}{100}=\frac{2}{5}.t$

$t = \frac{500.5}{100.2}$

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0

3 years ago