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goblinko [34]
2 years ago
9

From a hot-air balloon, Ian measures a 30^{\circ}

Mathematics
1 answer:
natka813 [3]2 years ago
5 0

The balloon’s vertical distance above the ground is 721.7 f

<h3>Angle of elevation and depression</h3>

In order to determine the balloon's vertical distance, we will use the SOH CAH TOA identity

Given the following parameters

Angle of depression = 30 degrees

Horizontal distance =1250 feet

Required

vertical distance H

Using the SOH CAH TOA identity

tan 30 = H/1250

H = 1250tan30
H = 721.7 feet

Hence the balloon’s vertical distance above the ground is 721.7 feet

Learn more on angle of elevation and depression here: brainly.com/question/2096694

#SPJ1

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Answer:

- 6.2

Step-by-step explanation:

The product of - 2 (3.1) is - 6.2.

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3 years ago
A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that
inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, H_0 : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, H_1 : p \neq 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

                T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } } ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

            \hat p = percentage of readers who own a particular make of car in a

                  sample of 220 = 0.30

            n = sample size = 220

So, Test statistics = \frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }

                             = -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

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Using this graph of f find f(6)
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4x , 6y
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