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larisa [96]
3 years ago
7

Help me solve for q! 21 + 3q < 3 (13 - q) How do you solve it? Thank you!

Mathematics
1 answer:
Molodets [167]3 years ago
8 0
Good morning

21 + 3q < 3(13 - q)
21+ 3q < 39 - 3q Here it was -3q and it was on the left side. However when you are switching it to another terms that looks like it you must change the sign as well.
3q + 3q < 39 - 21 Here I bring the common terms together.
6q < 18
Divide both sides by 6
6q/6 < 18/6
q < 3
 
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Hello can you please help me posted picture of question
MAXImum [283]
The answer is Letter C - 1/2,775

The probability of choosing one of them is 2 out of 75 while the probability of choosing the other one is 1 out of 74. 74 band members, not counting the other person (you or your bother).
 
Computation:
P = 2 / 75 * 1 / 74
   = 0.0266... * 0.01351...
   = 1 / 2,775
You can also multiply 75 with 74 to get a total of 5,550 then divide it by 2 students to be selected to get 2,775. Meaning one out of 2,775 possibilities.
8 0
3 years ago
I need this answer plzzz!!
Dmitriy789 [7]

Answer: True, False, False, False, False

<u>Step-by-step explanation:</u>

a) 5x - 7(x - 1)

   5x - 7x + 7

         -2x + 7   ⇒  a = -2, b = 7   <em>One Solution</em>

b) 3(x - 5) - 7

   3x - 15 - 7

       3x - 22   ⇒  a = 3, b = -22   <em>One Solution</em>

c) 2 - 7x + 3 + 4x

  4x - 7x + 3 + 2  

              -3x + 5  ⇒   a = -3, b = 5   <em>One Solution</em>    

d) -3(x - 3) - 1

   -3x + 9 - 1

       -3x + 8   ⇒   a = -3, b = 8   <em>One Solution</em>

e) -5x + 2 + 2x + 4

   -5x + 2x + 2 + 4

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4 0
3 years ago
19.5+24+7.5 =<br> 19.5+__+24 =<br> ___+24+___=
krek1111 [17]
See attached photo for solution

please give a thanks or brainliest if you found my answer helpful :)

8 0
3 years ago
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
Lesson 2-3
malfutka [58]

Answer:

18. g= -3

19. x= -1

20. n= 3

21. p= -1

22. d= -3

23. a= 5

Step-by-step explanation:

how to solve the variable (using 18 as an example)

step 1: simplify both sides of the equation.

20+g+g=14

(g+g)+(20)=14(combine like terms)

2g+20=14

2g+20=14

step 2: subtract 20 from both sides.

2g+20−20=14−20

2g=−6

step 3: divide both sides by 2.

2g/2 = -6/2

6 0
3 years ago
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