Ask question

Ask question

All categories

3 years ago

5

the distance d, in meters, that a rhinoceros runs in s seconds is represented by the equation d=16s. What is the constant of pro

portionality (unit rate) of d to s?

1 answer:

Akimi4 [234]3 years ago

5 0

Do you have notes from class?

You might be interested in

Jose wants to put a fence around his rectangular garden. His garden measures 31 feet by 33 feet. The garden has a path around it

vlabodo [156]

3 feet width is added to both sides .
so the dimensions become 34 feet and 36feet
hence the fencing length required or the perimeter= 2(l+b)
= 2( 34+36)
= 2(70)
= 140feet fence

4 0

3 years ago

Cam wants to find 509-106. Which steps can he use to find the difference

attashe74 [19]

Answer:403

Step-by-step explanation:

5 0 9

- 1 0 6

''''''''''''''"''""''''''

4 0 3

''''''''''''''''''''''''''''

5 0

3 years ago

Which expression is equivalent to -6 - ( -2 )<br><br> PLEASE HELP MEEE

katrin [286]

Answer:

-6 +2 = -4

Step-by-step explanation:

Its simple. Whenever you see two negative signs next to each other, they merge into an addition sign "positive".

-6+2 = -4

5 0

3 years ago

I need help with my math homework. <br> Find the slope of each line.<br> Thanks!

guajiro [1.7K]

7 is infinite 6 is 4/3 5 is zero 4 is negative 5/4

6 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

3 years ago