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kenny6666 [7]
3 years ago
8

A bag contains 13 dark chocolates, 16 white chocolates, and 11 milk chocolates. Maggie’s class teacher, Jill, is very strict, an

d the probability that she offers her students chocolates is 0.4. If Jill offers Maggie a chocolate from the bag, what is the probability that she randomly picks either a white chocolate or a milk chocolate? (NOTE: Add the probabilities of obtaining a white and milk chocolate individually)
Mathematics
1 answer:
Katarina [22]3 years ago
5 0
We are given with a bag containing 13 dark chocolates, 16 white chocolates, and 11 milk chocolates. hence the sample space is 13 + 16 + 11 equal to 40 chocolates. The <span> probability that she randomly picks a white chocolate is 16/40 or 2/5 and that she picks a milk chocolate is 11/40. Hence the probability of picking either is (16+11) /40 equal to 27/40</span>
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The schematic of a rectangular patio is drawn 1/4 inch to 1 feet. if the patio is 18 feet long, what is the measure of the patio
Aleksandr-060686 [28]
Try 4.5 inches. You take 18, divide it by four you get 4.5. I divided by 4 because of the 1/4 inch by 1 foot. Minus 2 from 18, you get the next closest dividend of 4 and that's 16. 16 divided by 4 is 4. 2 are left over to make .5. you get 4.5
6 0
3 years ago
-14(3a+6)=12(6-4a)+12 and steps please
Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

14(3a+6)+12(6-4a)+12=0 (using distributive property)

42a+84+72-48a+12=0 ( adding the like terms )

-6a+168=0

-6a=-168

6a=168

a=\frac{168}{6}

Therefore a=28

Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

8 0
3 years ago
Answer as soon as possible
alexandr1967 [171]

Answer:

C −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

(a+3) ( −2a^2+15a+6b^2)

Distribute the a to the large term in parentheses and the 3 to the large term in parentheses

a ( −2a^2+15a+6b^2)+3  ( −2a^2+15a+6b^2)

−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2

Combine like terms

−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2

-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2

3 0
3 years ago
Read 2 more answers
Please help with khan
kodGreya [7K]

Answer:

not 100% but I think it's Step 1

3 0
2 years ago
i need help with this i need the area found on the rectangle but ion know how to find it, plzzzz helpppppp!!!!!!!!!!! oh and ple
Ber [7]

Step-by-step explanation:

Tan30=4/adj

adj Tan 30= 4

adj=4/tan30

adj=6.93m

Area=L×b

4×6.93=27.72m

8 0
3 years ago
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