Answer:
Below is the graph which answers your question. Hopefully this helps :)
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Answer:
whenever you're multiplying terms that have exponents you multiply the coefficients and add their exponents:
Step-by-step explanation:
I think the answer to your first question should be:
30a²b - 30ab²
Your second answer is good
whenever you're multiplying terms that have exponents you multiply the coefficients and add their exponents:
for example, 6a²b³c x 2abc = 6(2)(a²)(a)(b³)(b)(c)(c)
= 12a³b⁴c²
Answer:
x=16 y=38
Step-by-step explanation:
x+y=54.......equation 1
x=y-22........ equation 2
substitute
y-22+y=54
2y-22=54
2y=54+22
2y=76
y=76/2
y=38''
x=y-22
x=38-22
x=16''
<span>A
and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1,
we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix)
and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>
19 would be the first quartile.
