Answer:
The Slope Intercept form of the equation through the point (0, -4) and
(1, 0) is y = 4 x - 1
Step-by-step explanation:
Here, the given points are A (0,-4) and B(1,0)
Now, slope of the equation with points (a,b) and (c,d) is given as
![m = \frac{d - b}{c -a}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7Bd%20-%20b%7D%7Bc%20-a%7D)
So, here the slope of the line AB is given as:
![m = \frac{0 - (-4)}{1-0} = \frac{4}{1} = 4](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B0%20-%20%28-4%29%7D%7B1-0%7D%20%3D%20%5Cfrac%7B4%7D%7B1%7D%20%20%3D%204)
⇒ m = 4
Now, by POINT SLOPE form:
The equation with slope m and point (x0 , y0) is represented as :
(y-y0) = m (x-x0)
⇒ The equation of AB is of the form with point (1,0) is
y - 0 = 4 (x -1)
or, y = 4 x - 1
Also, the SLOPE INTERCEPT form of an equation is of the form
y = m x + C ; m = slope and C = y -intercept
Hence, the slope intercept form of the equation through the point (0, -4) and (1, 0) is y = 4 x - 1