Answer:
c
Explanation: this is the correct answer
Answer:
- If they have one child, the probability that he or she will be affected is 1/4.
- If they have two children, the probability that at least one of them will be affected is 7/16.
Explanation:
A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.
Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.
Every time they have children new gametes were generated <u>independently</u>.
The probability of having <u>no</u> affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).
The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.
The answer to this question would be: start doing CPR.
If the victim becomes unresponsive, probably the foreign body completely obstructs the airway and the oxygen level is already too low. Without the victim help, taking out the foreign body will be hard.
In this case, CPR will be the best option since the pressure from chest might push the foreign body away and the CPR can help circulate the blood.
Answer:
Metaphase to Anaphase
Explanation:
Metaphase is when the chromosomes line up and Anaphase is when the chromosomes split apart.
1. Cranial roof & cranial base
2. Frontal bone, parietal bone, temporal bones, occipital bone, sphenoid bone, ethmoid bone
3. Inferior tribunal (2), lacrimal bones (2), mandibal, maxilla(2), nasal bones (2), palatine bones (2), vomer, zygomatic bones (2)