Answer:
Light is made up of wavelengths of light, and each wavelength is a particular colour. The colour we see is a result of which wavelengths are reflected back to our eyes. The visible spectrum showing the wavelengths of each of the component colours. The spectrum ranges from dark red at 700 nm to violet at 400 nm.The 'colour' of an object is the wavelengths of light that it reflects. This is determined by the arrangement of electrons in the atoms of that substance that will absorb and re-emit photons of particular energies according to complicated quantum laws.The reason that different waves of light appear to be different colors of light is because the color of a light wave depends on its wavelength. For example, the wavelength of blue light is about 450 nanometers, while the wavelength of red light is about 700 nanometers.
Explanation:
Photosynthesis produces glucose and oxygen.... Respiration on the other hand would produce the other options.
The scientist which was credited with first stating that electrons orbit an atomic nucleus was Niels Henrik David Bohr. He was the proponent of the Bohr model of the atom, wherein he states that energy level of electrons are distinct and that electrons revolve on stable orbits within the atomic nucleus but can actually transfer from one orbit (level) to another. The orbitals are called: s, p, d and f orbitals.
The lowest smallest whole-number coefficient for H₂S is 5. Option C
<h3>What is the smallest whole-number coefficient for H₂S?</h3>
Now we know that a redox reaction is one in which there is a loss and gain of electrons One specie is oxidized (looses electrons) while another specie is reduced (gains electrons). The electrons must be transferred leading to an increase in oxidation number of one specie and a decrease in the oxidation number of another.
Now the reduction half equation is;
MnO4^-(aq) + 8H^+(aq) + 5e^- ----> Mn^2+(aq) + 4H2O (l)
The oxidation half equation is;
H2S(aq) ----> S^2-(aq) + 2H^+(aq) + 2e^-
Multiplying the reduction half equation by 2 and the oxidation half equation is 5
2MnO4^-(aq) + 16H^+(aq) + 10e^- ----> 2Mn^2+(aq) + 8H2O (l)
And;
5H2S(aq) ----> 5S^2-(aq) + 10H^+(aq) + 10e^-
The overall balanced reaction equation is;
2MnO4^-(aq) + 6H^+(aq) + 5H2S(aq) ----> 2Mn^2+(aq) + 8H2O (l) + 5S^2-(aq)
Thus the lowest smallest whole-number coefficient for H₂S is 5.
Learn more about redox reaction:brainly.com/question/13293425
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I'm pretty sure it's Ca2+ and F- because Ionic bonds are metals and nonmetals