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Answer: We will use the electron-dot structure to tell the reactivity of fluorine.
Explanation: Fluorine atom is the 9th element of the periodic table.
Atomic number: 9
Electronic configuration of fluorine = 
The number of valence electrons = 7
and the valency for this element = 1 (because this element requires only one electron to have a stable electronic configuration)
Electron dot structures are the structures which represent the valence electrons present around the nucleus of an atom. The dots in the structures represent the electrons.
Reactivity of an element is defined as its ability to gain or loose electrons easily.
As fluorine atom gains 1 electron easily, so it is very reactive.
Electron dot structure of fluorine atom is given in the image attached.
Answer:
Explanation:
The graph shows the phase diagram of water . From it , it is clear that at 100°C water remains in equilibrium with water vapour and at this temperature , the vapour pressure is equal to one atm . So this must be boiling point of water.
At 0.7 atm pressure , boiling point must have been reduced . So when water is at 100°C , it must have been completely in vapour phase .
Now the pressure is increased to 1.4 atm . In this process of increase of pressure , the water in vapour state must have turned into liquid state as soon as the pressure increases beyond 1 atm . Beyond it its boiling point would have increased above 100°C so it can not remain in gaseous phase . At 1.4 atm , its boiling point would have increased to 110°C or so . Hence it must be in liquid phase because its temperature is below its boiling point at that pressure .
Hence water changes from gaseous phase to liquid phase when pressure changes from 0.7atm to 1.4 atm .