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2 years ago

What is microorganisms

Chemistry

1 answer:

Wewaii [24]2 years ago

4 0

Answer:

Technically a microorganism or microbe is an organism that is microscopic. The study of microorganisms is called microbiology. Microorganisms can be bacteria, fungi, archaea or protists. The term microorganisms does not include viruses and prions, which are generally classified as non-living.

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Identify each of the following household substances as a strong electrolyte, weak electrolyte, or non-electrolyte: salt solution

wolverine [178]

Answer:

Electrolytes are substances that can ionize in water. They could be acids, bases or salts as long as they give ions when they dissolve in water.

Explanation:

Strong electrolytes completely ionize when dissolved in water, leaving no neutral molecules. The strong electrolytes here are: salt water, baking soda (NaHCO3) solution.
Weak electrolytes do not completely dissociate in solution, and hence have a low ionic yield. Examples of this would be vinegar and bleach (which could be sodium hypochlorite or chlorine, which are weakly dissociated).
Non-electrolytes will remain as molecules and are not ionized in water at all. In this case, sugar solution is a non-electrolytes, even though sugar dissolves in water, but it remains as a whole molecule and not ions.

8 0

3 years ago

How many moles of pcl5 can be produced from 28.0 g of p4 (and excess cl2)?

BARSIC [14]

P₄ + 10Cl₂ ---> 4PCl₅
stoichiometry of P₄ to PCl₅ is 1:4
number of moles of P₄ reacted - 28.0 g / 124 g/mol = 0.22 mol
Cl₂ is in excess therefore P₄ is the limiting reactant, amount of product formed depends on amount of limiting reactant present
according to molar ratio of 1:4
number of PCl₅ moles formed -0.22 mol x 4 = 0.88 mol
0.88 mol of PCl₅ is formed

5 0

3 years ago

How many moles of PC15 can be produced from 58.0 g of Cl₂ (and excess P4)?

ludmilkaskok [199]

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

$P_{4} + 10Cl_{2} = 4PCl_{5}$

The mass of clorine is m( $Cl_{2}$ ) = 58.0 g

The amount of clorine is n( $Cl_{2}$ ) = m( $Cl_{2}$ )/M( $Cl_{2}$ ) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of $Cl_{2}$ yield 4 moles of $PCl_{5}$ ;

0.817 of $Cl_{2}$ yield x moles of $PCl_{5}$

n( $PCl_{5}$ ) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

#SPJ9

3 0

1 year ago

Number of elments in hcooh

igomit [66]

3 elements are present in HCOOH - hydrogen, oxygen, and carbon.

7 0

2 years ago

Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. C

Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

6 0

2 years ago