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givi [52]
3 years ago
15

Ethanol, C2H6O, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is

a renewable resource and ethanol-blended fuels, like gasohol, appear to burn more efficiently in combustion engines. The heat of combustion of ethanol is 326.7 kcal/mol. The heat of combustion of octane, C8H18, is 1.308×103 kcal/mol. How much energy is released during the complete combustion of 354 grams of octane ?
Chemistry
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

4054 kcal of heat is released during complete combustion of 354 g of octane.

Explanation:

Heat of combustion of 1 mol of octane is 1.308\times 10^{3} kcal

Molar mass of octane = 114.23 g/mol

We know, no. of moles = (mass)/(molar mass)

So, 1.308\times 10^{3} kcal of heat is released during complete combustion of 114.23 g of octane.

So, amount of heat is released during complete combustion of 354 g of octane = (\frac{1.308\times 10^{3}}{114.23})\times 354  kcal = 4054 kcal

Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.

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The answer would be D

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109.5

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1. Find the number of protons, neutrons, electrons and electronic structure of flourine 919F.
77julia77 [94]

1. ₉¹⁹F

2. Mg(OH)₂

3. 2H₂ + O₂ ⇒ 2H₂O

<h3>Further explanation</h3>

1. Fluorine, atomic number : 9 , mass number = 19

Symbol : ₉¹⁹F

protons=electrons=atomic number = 9

neutrons = mass number - atomic mass

\tt n=19-9=10

Configuration : [He] 2s² 2p⁵

2. Magnesium hydroxide is an ionic compound and is a strong base consisting of 2 ions:

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negative ion: Hydroxide: OH⁻

The charges of the two are crossed, so that the compound becomes:

Mg(OH)₂

3. Reaction :

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give coefficient :

aH₂ + bO₂ --------> H₂O

H, left = 2a, right 2⇒2a=2⇒a=1

O, left = 2b, right 1⇒2b=1⇒b=0.5

Reaction becomes :

H₂ + 0.5O₂ --------> H₂O x 2

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4 0
3 years ago
The Tin Pan Alley era lasted from 1950 to 1967.<br> a. true<br> b. false
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An object was measured by a worker as
Gre4nikov [31]

Answer:

\boxed{2.8 \, \%}

Explanation:

\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%

Data:

Predicted = 17.4 cm

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Calculation:

\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}

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3 years ago
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