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MAVERICK [17]
4 years ago
14

Evaluate each expression 9y2 - 7 for y =3

Mathematics
1 answer:
lesantik [10]4 years ago
7 0
9 y² - 7   for y = 3

9 * 3² - 7 = 

9 * 9 - 7 =

81 - 7 => 74 


You might be interested in
1.
Viktor [21]

Answer:

g(x) = (x - 4)^2 - 5, and the vertex is (4, -5)

Step-by-step explanation:

Please, use " ^ " to indicate exponentiation:  g(x) = (x - 4)^2 – 5.  Comparing this to y = a(x - h)^2 + k, we see that h must be 4 and k must be -5.  Thus, the vertex is (4, -5).

Make a table showing several x-values and the corresponding y-values:

x       g(x) = (x - 4)^2 - 5                     (x, y)

0                    (-4)^2 - 5 = 11               (0, 11)

4                (4 - 4)^2 - 5 = -5               (4, -5)

8 0
3 years ago
Someone please answer this it’s due today I need help
alisha [4.7K]

Answer:

x = 8

Step-by-step explanation:

3x - 5 = 2.5x + 3 - (x - 4)

<em>open parentheis</em>

3x - 5 = 2.5x + 3 - x + 4

3x - 5 = 1.5x + 7

<em>subtract 1.5x from both sides of the equation</em>

3x - 1.5x - 5 = 7

1.5x - 5 = 7

<em>add 5 to both sides of the equation</em>

1.5x = 7 + 5

1.5x = 12

<em>divide both sides of the equation by 1.5</em>

1.5x/1.5 = 12/1.5

x = 12/1.5

x = 8

3 0
3 years ago
Find the missing segment below brainly
Aleksandr-060686 [28]

Let it be x

\\ \sf\longmapsto \dfrac{4}{10}=\dfrac{x}{12+x}

\\ \sf\longmapsto 4(12+x)=10x

\\ \sf\longmapsto 48+4x=10x

\\ \sf\longmapsto 10x-4x=48

\\ \sf\longmapsto 6x=48

\\ \sf\longmapsto x=\dfrac{48}{6}

\\ \sf\longmapsto x=8

8 0
3 years ago
A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa
PSYCHO15rus [73]

Answer:

A) \dfrac{11}{23}

B) \dfrac{88}{345}

Step-by-step explanation:

A survey of 46 college athletes found that

  • 24 played volleyball,
  • 22 played basketball.

A) If we pick one athlete survey participant at random,  the probability they play basketball is

P_1=\dfrac{22}{46}=\dfrac{11}{23}

B) If we pick 2 athletes at random (without replacement),

  • the probability we get one volleyball player is \dfrac{24}{46}=\dfrac{12}{23};
  • the probability we get another basketball player is \dfrac{22}{45} (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}

5 0
4 years ago
All of the following equations have the same solution except _____.
mrs_skeptik [129]
This is if you need it written out, but the answer would be the last one 3m+2=-10 doesn’t have the same solution as the rest

5 0
4 years ago
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