All categories

2 years ago

Find the midpoint of segment AB given. A (-3, 2) and B (3, -2)

Mathematics

1 answer:

Tasya [4]2 years ago

8 0

$\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ A(-3,\ 2)\ \text{and}\ B(3,\ -2).\ \text{Substitute:}\\\\x=\dfrac{-3+3}{2}=\dfrac{0}{2}=0\\\\y=\dfrac{2+(-2)}{2}=\dfrac{0}{2}=0\\\\Answer:\ \boxed{(0,\ 0)}$

You might be interested in

If p(x)=2x^2-4x and q(x)=x-3 what is (p*q)(x)

Tanya [424]

Answer: 2x³-10x²+12x or 2x(x²-5x+6)

Step-by-step explanation:

(p*q)(x) means p(x) and q(x) multiplied together.

(2x²-4x)(x-3)

2x³-6x²-4x²+12x

2x³-10x²+12x

You can also factor this by taking out a 2x.

2x(x²-5x+6)

4 0

2 years ago

Grade 7th math anybody know the answer

TiliK225 [7]

Our answer is attached.

I hope it helped.

4 0

2 years ago

Solve.<br> Subtract 6x2 – X – 7 from the product of x2 + x + 5 and x - 6.

tresset_1 [31]

Answer:

x ^ 3 − 11 x ^ 2 + X - x − 23

Step-by-step explanation:

you have to Simplify the expression. Hope that helped!! :)

PLEASE MARK BRAINLIEST!!

8 0

2 years ago

Machine A makes 12.75 ounces of popcorn in 3 minutes. Machine B makes 18 ounces of popcorn in 4 minutes. If each machine makes p

melamori03 [73]

Answer: Machine A makes popcorn at a rate of 4.25 ozs per minute (12.75oz/3min).

Machine B makes popcorn at a rate of 4.5 ozs per minute (18oz/4min).

Machine A will make 4.25oz/min * 10minutes = 42.5oz of popcorn after 10 minutes

Machine B will make 4.5oz/min * 10 minutes = 45oz of popcorn after 10 minutes

After 10 minutes there will be a total of 42.5oz (Machine A) +45oz (Machine B) = 87.5oz.

So the answer is: Yes there will be (more than) enough popcorn if both machines make popcorn for 10 minutes.

If the question is wondering how many 9oz bags they can fill: 87.5oz/9oz per bag = 9.7222 bags. The machines can fill 9, 9oz, bags with some popcorn leftover.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is a

Lyrx [107]

Answer:

A) 0

Step-by-step explanation:

When x is divided by 11, we have a quotient of y and a remainder of 3

x/11 = y + 3

x = 11y + 3 ........(1)

When x is divided by 19, we have a remainder of 3 also

x/19 = p + 3 (p = quotient)

x = 19p + 3 ..........(2)

Equate (1) and (2)

x = 11y + 3 = 19p + 3

11y + 3 = 19p + 3

11y = 19p + 3 -3

11y = 19p

Divide both sides by 11

11y/11 = 19p/11

y = 19p/11

y and p are integers. 19 is a prime number. P/11 is also an integer

y = 19(integer)

This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0

8 0

2 years ago