Firstly, seeing that the sequence is based on odd numbers I would say that this is the formula (which will allow you to know whatever term):
nth term = 2n-1
Hope this helps!
68-40=28
28/4=7
therefore, 7 is your answer
(Hope it helps my friend ^_^)
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
First, we must let:
x = number of tickets intended for adults
y = number of tickets intended for children.
a. Write in terms of x the number of tickets for children
Solution:
x + y = 28 ⇔ y = 28 - x (equation 1)
To answer in terms of x:
no. of tickets for tickets for children = 28 - x
b. the amount spent on tickets for adults
Solution: $30 is the cost of ticket per adult and there are x number of tickets intended for adults.
Therefore,
amount spent on ticket for adults = 30x
c. the amount spent on the tickets.
Solution:
$ 15 = cost of ticket per child
$ 30 = cost of ticket per adult
total amount spent on tickets = 30x + 15y ⇒ (equation2)
substitute equation 1 to equation 2.
(equation 1) y = 28 - x
(equation 2) total amount spent on tickets = 30x + 15y
total amount spent on tickets = 30x + 15(28-x)
total amount spent on tickets = 30x + 420 - 15x
total amount spent on tickets = 15x + 420
Answer:
See possible solutions below.
Step-by-step explanation:
The statements are not given. But the following can be determined from the graph:
- More days recorded temperatures between 82 and 84 then other temperatures.
- The least number of days recorded temperatures between 88 and 90.
- The histogram is skewed to the right also known as positive skewed distribution.
- The mean and median will most likely be in the range of 82-84 temperatures. But the mean will be greater than the median.
