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zhannawk [14.2K]
3 years ago
5

A repair company’s charge for repairing a certain type of copy machine fits the model y = 47.38 + 0.617x where y is the number o

f dollars charged and x is the number of minutes the repair person is on the job. How many minutes would it take for the cost of repair to reach $70?
Mathematics
1 answer:
Tems11 [23]3 years ago
6 0

Answer: 36.66min

Step-by-step explanation:

y = 47.38 + 0.617x

where y is the number of dollars

x is the number of minutes on the job

Given a value of y = $70, then

We substitute y = $70 in the equation.

70 = 47.38 + 0.617x

22.62 = 0.617x

X = 22.62/0.617 = 36.66min

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Answer:

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P(x

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P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

Therefore, the probability is P(8<x<13)=0.3.

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You have 9:30am classes three times a week.  So, we get:

P=0.6^3=0.216

Therefore, the probability is P=0.216.

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P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

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Answer:

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