ΔG° at 450. K is -198.86kJ/mol
The following is the relationship between ΔG°, ΔH, and ΔS°:
ΔH-T ΔS = ΔG
where ΔG represents the common Gibbs free energy.
the enthalpy change, ΔH
The temperature in kelvin is T.
Entropy change is ΔS.
ΔG° = -206 kJ/mol
ΔH° equals -220 kJ/mol
T = 298 K
Using the formula, we obtain:
-220kJ/mol -T ΔS° = -206kJ/mol
220 kJ/mol +206 kJ/mol =T ΔS°.
-T ΔS = 14 kJ/mol
for ΔS-14/298
ΔS=0.047 kJ/mol.K
450K for the temperature Completing a formula with values
ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol
ΔG° = -220 kJ/mol + 21.14 kJ/mol.
ΔG°=198.86 kJ/mol
Learn more about ΔG° here:
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Hi! My answer would be D, USA.
Explanation:
We are provided with 5 pieces of an address. They are as followed.
12 Riverdale Lane, Apartment A, San Jose, California, and USA.
Imagine each of the five parts of Beck's address represents Earth, the Milky Way, the moon, the solar system, or the universe, based on their sizes. Which of the following parts of Beck's address would represent the solar system?
If we have to plug in Earth, the Milky Way, the moon, the solar system, and the universe, (all based on size,) we would first start with what "Apartment A" would be in this scenario. Apartment A is the smallest piece we have to work with, and so is the moon. This leads me to believe that the Moon should be plugged into Apartment A. Now, 12 Riverdale Lane is most likely going to be the Earth, since it is the second smallest one on our list. San Jose would turn into the Sun, California represents the Milky Way, and USA represents the solar system.
I sincerely hope I helped!
Have a wonderful day :)
~AmbitiousAndProud
Answer:
Explanation:
Oxygen has eight eletrons and six valence electrons, giving it the electron configuration of .
Answer: Option (E) is the correct answer.
Explanation:
Since, the conductor is hollow which means that it is opened on both the ends. Hence, when a small uncharged metal ball is passed through it with the help of a silk thread then due to the presence of this insulating thread the ball will not come directly in contact with the charged rod.
As a result, there will occur no formation of opposite charge on the metal ball. Therefore, the ball will remain uncharged in nature.
Thus, we can conclude that after the given ball is removed, it will have no appreciable charge.
The question that will best help the student to classify the material is; "is the material malleable or ductile?"
Generally, materials can be classified as metals or non metals. There are properties that are particular to metals and there are properties that are particular to nonmetals and these properties can be used to identify each one of the materials.
The question that will best help the student to classify the material is; "is the material malleable or ductile?" These metallic properties.
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Missing parts;
A student is trying to classify an unidentified, solid gray material as a metal or a nonmetal. Which question will best help the student classify the material? A. Is the material malleable or ductile? B. Does the material feel hard to the touch? C. Will the material float in water? D. Does the material feel rough or smooth?
