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konstantin123 [22]
3 years ago
12

Acetic acid (ch3cooh) can be a buffer, similar to carbonic acid. write the dissociation reaction, identifying the acid, base, h+

acceptor, and h+ donor.
Chemistry
1 answer:
BARSIC [14]3 years ago
3 0
The dissociation of acetic acid in water can be written as:

CH₃COOH + H₂O ↔ CH₃COO⁻ + H₃O⁺

The proton donor is CH₃COOH 
The proton acceptor is H₂O 
The acid is CH₃COOH 
The conjugate base is CH₃COO⁻
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2 years ago
Read 2 more answers
If you can solve both<br> Will mark brainly<br> ASAP
MrRa [10]

Answer:

The main function sis the 2nd one and the substance provides the first 1.

Explanation:

Hope you finish the rest on your own, have fun!

7 0
3 years ago
Please help me with this chem question, I’ll mark you brainiest if it’s right. There’s multiple answers for this one.
Kazeer [188]

Answer:

Option A. KCl (aq)

Option D. Mg(OH)₂(s

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

MgCl₂(aq) + KOH(aq) —>

In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

KOH(aq) —> K⁺(aq) + OH¯(aq)

MgCl₂(aq) + KOH(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)

MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)

Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)

Thus, option A and D gives the correct answer to the question.

8 0
2 years ago
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