The term “electricity” in referring to static electricity, means what

1 answer:

5 0

Is an imbalance of electric charges within or on the surface of a material. The charge remains until it is able to move away by means of an electric current or electrical discharge. Static electricity is named in contrast with current electricity, which flows through wires or other conductors and transmits energy.[1]

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Please help asap! giving brainliest to correct answer!!

vlabodo [156]

Answer:

D. C₄H₁₀ and C₂H₅

<h2>What is a empirical formula?</h2>

A chemical formula indicating the elements of a compound and their relative proportions, as (CH₂O)n.

Since an empirical formula indicates the ratio (proportions) of the elements in the compound, it can be used, along with the molar weight of the compound, to determine the molecular formula.

The empirical formula provides the smallest whole-number ratio among elements or compounds within a molecular compound. A compound is a chemical formed from atoms of different chemical elements.

Hence, Option D is correct.

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4 0

1 year ago

Plzz help guyss I'm so confused

Serga [27]

5 because A=v/t 20/4=5

8 0

2 years ago

Combustion reactions are exothermic. The heat of reaction for the combustion of 2-methylheptane, C8H18, is 1.306×103 kcal/mol. W

WARRIOR [948]

Answer:

11.45kcal/g

2.612 × 10³ kcal

Explanation:

When a compound burns (combustion) it produces carbon dioxide and water. The combustion of 2-methylheptane can be represented by the following balanced equation:

2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O

It releases 1.306 × 10³ kcal every 1 mol of C₈H₁₈ that is burned.

<em>What is the heat of combustion for 2-methylheptane in kcal/gram?</em>

We know that the molar mass of C₈H₁₈ is 114.0g/mol. Then, using proportions:

$\frac{1.306 \times 10^{3}Kcal}{1mol} .\frac{1mol}{114.0g} =11.45kcal/g$

<em>How much heat will be given off if molar quantities of 2-methylheptane react according to the following equation? 2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O</em>

In this equation we have 2 moles of C₈H₁₈. So,

$2mol \times\frac{1.306 \times 10^{3}kcal }{1mol} =2.612\times 10^{3}kcal$