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labwork [276]
3 years ago
8

The diameter of carbon atom is.000000000154m. What is this expressed in scientific notation.

Chemistry
1 answer:
Margarita [4]3 years ago
5 0

1.54 x 10^-10

thats the answer

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How does increasing temperature increase the number of reactions?
antiseptic1488 [7]

Answer:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction

Explanation:

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When an acid solution exactly neutralizes a base
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Answer:a weak acid and a weak base

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A scuba diver goes deeper underwater the diver must be aware that the increased pressure affects the human body be increasing th
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The amount of dissolved gases in the body. Have a good day! =)

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3 years ago
Milk of magnesia, a suspension of mg(oh)2 in water, reacts with stomach acid (hcl) in a neutralization reaction. mg(oh)2(s) + 2
defon
Balanced equation for the above reaction is as follows;
Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O
stoichiometry of Mg(OH)₂ to MgCl₂ is 1:1
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number of Mg(OH)₂  moles reacted - number of MgCl₂ moles formed 
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5 0
3 years ago
A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She found that the equilibrium
Alexandra [31]

Answer:

(a). 4°C, (b). 2.4M, (c). 11.1 g, (d). 89.01 g, (e). 139.2 g and (f). 58 g/mol.

Explanation:

Without mincing words let's dive straight into the solution to the question.

(a). The freezing point depression can be Determine by subtracting the value of the initial temperature from the final temperature. Therefore;

The freezing point depression = [ 1 - (-3)]° C = 4°C.

(b). The molality can be Determine by using the formula below;

Molality = the number of moles found in the solute/ solvent's weight(kg).

Molality = ( 11.1 / 58) × (1000)/ ( 90.4 - 11.1) = 2.4 M.

(c). The mass of acetone that was in the decanted solution = 11.1 g.

(d). The mass of water that was in the decanted solution = 89.01 g.

(e). 2.4 = x/ 58 × (1000/1000).

x = 2.4 × 58 = 139.2 g.

(f). The molar mass of acetone = (12) + (1 × 3) + 12 + 16 + 12 + (1 x 3) = 58 g/mol.

7 0
3 years ago
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