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Nataly_w [17]
3 years ago
6

Care sunt factorii de poluare a aerului?

Chemistry
1 answer:
bulgar [2K]3 years ago
8 0

Answer:

Arderea de combustibili fosili, activități agricole, eșapament din fabrici și industrii, operațiuni miniere și poluarea aerului interior

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Please explain your answer! <br><br> Thanks!
Yuri [45]
Hello Gary!
*Sorry if I'm late*

Your answer is going to be 65.
Element A (which is actually Zinc) has the atomic number of 65. (I remember having got memorize this also).
Pretty much the explanation is that the number of patrons is equivalent to the element's atomic number!

Hope this helps!
Have a nice day :D
8 0
3 years ago
Read 2 more answers
What is the balanced chemical equation for the reaction of aqueous sodium hydroxide and sulfuric acid?
Andrews [41]

Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

6 0
3 years ago
All atoms of the same element contain the same number of protons. the atom that has 9 protons can be represented by the symbol?
padilas [110]

It can be represented by atom -9

It would be Fluorine in real..

5 0
3 years ago
Please help, I'm so confused!!!!
masha68 [24]

Answer:

\boxed {\boxed {\sf N_2}}

Explanation:

Let's examine this reaction, especially the coefficients.

N_2+3H_2 \rightarrow 2NH_3

First of all, remember that reactants are used to make the product. They are found on the left of the arrow usually. Therefore, N₂ and H₂ are the reactants, while NH₃ is the product. We can automatically eliminate NH₃ from our answer choices, because it is simply not a reactant.

Next, look at the coefficients.

  • N₂ has no coefficient, so a 1 is implied.
  • H₂ has a coefficient of 3.

Therefore, for the reaction to work, there must be 1 mole of N₂ and 3 moles of H₂.

We have 3.2 moles of N₂ and 5.4 moles of H₂.

Divide each amount given by the required amount for completion.

  • 3.2 mol N₂/ 1 mol N₂= 3.2 times
  • 5.4 mol H₂/ 3  mol H₂=1.8 times

Therefore, there is enough nitrogen to complete the reaction 3.2 times, but only enough hydrogen for 1.8 times. If everything is completely reacted, we will run out of hydrogen and have excess <u>nitrogen</u>.

6 0
3 years ago
Kc is 1.67 x 10^20 at 25 °C for the formation of iron(III) oxalate complex ion:
Liula [17]

Answer:

n_{C_2O_4^{2-}}=1.59mol C_2O_4^{2-}

Explanation:

Hello there!

In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:

Kc=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[Fe^{3+}][C_2O_4^{2-}]^3}

However, according to the question, we just need to apply the given 1:3 mole ratio in the chemical reaction, of iron (III) ions to oxalate ions to obtain:

n_{C_2O_4^{2-}}=0.53molFe^{3+}*\frac{3molC_2O_4^{2-}}{1molFe^{3+}}=1.59mol C_2O_4^{2-}

Regards!

7 0
3 years ago
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