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2 years ago

The table compares the frequency of some unknown electromagnetic waves,

Chemistry

1 answer:

Sedaia [141]2 years ago

5 0

Answer:

Wave X

Explanation:

because the lower the frequency, the longer the wave length

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Aluminum metal reacts with bromine, a red-brown liquid with a noxious odor. The reaction is vigorous and produces aluminum bromi

GuDViN [60]

Answer: The mass of bromine reacted is 160.6 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium = 18.1 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium}=\frac{18.1g}{27g/mol}=0.670mol$

The chemical equation for the reaction of aluminium and bromide follows:

$2Al+3Br_2\rightarrow 2AlBr_3$

By Stoichiometry of the reaction:

2 moles of aluminium reacts with 3 moles of bromine gas

So, 0.670 moles of aluminium will react with = $\frac{3}{2}\times 0.670=1.005mol$ of bromine gas.

Now, calculating the mass of bromine gas, we use equation 1:

Moles of bromine gas = 1.005 moles

Molar mass of bromine gas = 159.81 g/mol

Putting values in equation 1, we get:

$1.005mol=\frac{\text{Mass of bromine}}{159.81g/mol}\\\\\text{Mass of bromine}=(1.005mol\times 159.81g/mol)=160.6g$

Hence, the mass of bromine reacted is 160.6 grams.

5 0

3 years ago

What tool is used in an explosion site to chemically detect explosive residues on objects?

qaws [65]

Answer:

ion mobility spectrometer

Explanation:

it is an handheld chemical dectection device

Hope this helps

Please mark me as Brainliest

8 0

3 years ago

A chiral amine A having the R configuration undergoes Hofmann elimination to form an alkene B as the major product. B is oxidati

Free_Kalibri [48]

Answer:

The Structure of "B" is alkene.

Explanation:

The compound "A" having R- configuration and undergoes Hofmann elimination to form an alkene.

The compound "B" on oxidatively cleaving with ozone followed by dimethyl sulfide forms $CH_{2}=S$ and $CH_{3}CH_{2}CH_{2}CHO$

The structure of "A" and"B" is as follows.

3 0

4 years ago

How quickly do the magnetic poles switch sides

nexus9112 [7]

Idk but it is probably fast

4 0

3 years ago

A 25.0-mL sample of an H2SO4 solution requires 50.0 mL of 0.150 M NaOH to completely react with the H2SO4. What was the concentr

Nitella [24]

V( H₂SO₄) = 25.0 mL in liters = 25.0 / 1000 = 0.025 L
M(H₂SO₄) = ?

V(NaOH) = 50.0 mL = 50.0 / 1000 = 0.05 L
M(NaOH) = 0.150 M

number of moles NaOH :

n = M x V

n = 0.150 x 0.05

n = 0.0075 moles of NaOH

H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)

1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0075 moles NaOH

moles = 0.0075 * 1 / 2

= 0.00375 moles of H₂SO₄

M(H₂SO₄) = n / V

M = 0.00375 / 0.025

= 0.15 M

hope this helps!

8 0

3 years ago