What two values of x are roots of the polynomial??
1 answer:
The correct answer would be C.
In order to solve for this you must first get the equation equal to 0. Luckily for you, it already is in that form.
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 4 (because it is the coefficient to x^2)b = -6 (because it is the coefficient to x)c = 1 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers
In order to solve for this you must first get the equation equal to 0. Luckily for you, it already is in that form.
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 4 (because it is the coefficient to x^2)b = -6 (because it is the coefficient to x)c = 1 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers
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Answer:
We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.
Step-by-step explanation:
We are given that Location A was observed for 18 days and location B was observed for 13 days.
On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.
<em>Let </em><em> = true mean number of sales at location A.</em>
<em /> = <em>true mean number of sales at location B</em>
So, Null Hypothesis, :
or
{means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}
Alternate Hypothesis, :
or
{means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}
The test statistics that would be used here <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;
T.S. = ~
where, = sample average of items sold at location A = 39
= sample average of items sold at location B = 49
= sample standard deviation of items sold at location A = 8
= sample standard deviation of items sold at location B = 4
= sample of days location A was observed = 18
= sample of days location B was observed = 13
Also, =
= 6.64
So, <u><em>test statistics</em></u> = ~
= -4.14
The value of t test statistics is -4.14.
Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.
<em>Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>
Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.