Question

What two values of x are roots of the polynomial??

Answer 1

The correct answer would be C.
In order to solve for this you must first get the equation equal to 0. Luckily for you, it already is in that form. 
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 
a = 4 (because it is the coefficient to x^2)b = -6 (because it is the coefficient to x)c = 1 (because it is the end number)
Now we can plug these values into the quadratic equation. 
$\frac{-b +/- \sqrt{ b^{2} -4ac} }{2a}$

$\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}$

$\frac{6 +/- \sqrt{ 20 }{8}$

And those would be your two answers