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Paul [167]
3 years ago
7

_______ are organisms that recycle nutrients from decaying organic material.

Biology
1 answer:
drek231 [11]3 years ago
4 0

Answer:

Decomposers

Explanation:

Decomposers decompose organic material, effectively recycling it.

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Which of the following statements describes an example of natural selection?
nignag [31]
An aloe vera plant possessing a trait for extra thick leaves survives very long droughts in deserts, while and aloe vera plant that doesn't have thick leaves doesn't.
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4 years ago
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Explain the adaptations for root hair cell
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Answer:

they have thin membranes to allow diffusion of substance for short distance

they are numerous to increase the surface area of absorption

hope this helps

8 0
3 years ago
Plsssss help rn and pls don’t guess.
asambeis [7]

Answer:

Punnett Squares are unable to predict the offspring of an asexual organism because there is only one parent from which the offspring can receive genes from. The whole point of a Punnett Square is the fact that it covers all possible  offspring outcomes besides mutations from the usual two parents.

3 0
3 years ago
Factorize this polynomial function <br>x³-7x+6<br>Hint:x³-7x+6​=0
dolphi86 [110]

Answer:

(x - 1)(x - 2)(x + 3)

Explanation:

f(x)=x3-7x+6 Since (a + b + c + d = 0), then f(1) = 0 --> one factor if (x - 1).

After division -->

f(x)=(x-1)(x2f2+x-6). The trinomial in parentheses can be factored.

Find 2 numbers knowing sum (1) and product (-6). They are -2 and 3.

Therefor, f(x)=(x-1)(x-2)(x+3)

5 0
3 years ago
small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi
irina [24]

Answer:

Frequency of p = 0.684

Frequency of p = 0.316

Number of individuals with homozygous dominant (AA) = 47

Number of individuals with heterozygous (Aa)= 43

Number of individuals with homozygous recessive (aa) = 10

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals (q^{2}) is \frac{10}{100} = 0.1

Now, q will be

= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316

As per Hardy Weinberg's equation -

p + q = 1

Substituting the value of q in above equation, we get -

p + 0.316 = 1p = 1 -0.316\\p = 0.684

Now the frequency of homozygous dominant (AA) will be

p^{2} = 0.684^{2} \\= 0.467

Hence, out of 100 people 0.467 * 100 = 46.7 or 47 people are homozygous dominant (AA)

Like wise out of 100 people 0.1 * 100 = 10 people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

p^{2} + q^{2} + 2pq = 1\\

Substituting the values in above equation, we get -

0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433

So, out of 100 people 0.433 * 100 = 43.3 or 43 people are heterozygous (Aa)

7 0
4 years ago
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