Write log7(2 ⋅ 6) + log73 as a single log.
2 answers:
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Answer:
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Step-by-step explanation:
The problem states that the monthly cost of a celular plan is modeled by the following function:
In which C(x) is the monthly cost and x is the number of calling minutes.
How many calling minutes are needed for a monthly cost of at least $7?
This can be solved by the following inequality:
For a monthly cost of at least $7, you need to have at least 100 calling minutes.
How many calling minutes are needed for a monthly cost of at most 8:
For a monthly cost of at most $8, you need to have at most 110 calling minutes.
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Given:
The piecewise function is
To find:
The range of given piecewise function.
Solution:
Range is the set of output values.
Both functions and
as linear functions.
Starting value of is at x=-4 and end value is at x=3.
Starting value:
End value:
Starting value of is at x=3 and end value is at x=6.
Starting value:
End value:
Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.
Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.
So, the range of the given piecewise function is [0,11).
Therefore, the correct option is A.