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Leona [35]
3 years ago
12

Write log7(2 ⋅ 6) + log73 as a single log.

Mathematics
2 answers:
MariettaO [177]3 years ago
6 0
Log7 36 is the correct answer.
Marina86 [1]3 years ago
6 0

Answer:

   log₇(2 x 6) + log₇3 = log₇ 36

Step-by-step explanation:

We have the result

            log A + log B =  log AB

Here the question is log₇(2 x 6) + log₇3.

Using the result we will get,

            log₇(2 x 6) + log₇3 = log₇(2 x 6 x 3)  =log₇ 36

So,   log₇(2 x 6) + log₇3 = log₇ 36

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5(17+13) ÷(8-7) <br> Simply the expression
Scrat [10]
First expand by multiplying
Do 5 x 17=85
Then 5 x 13= 65
As them
85+65=150
8-7=1
150/1=150
Answer-150
8 0
3 years ago
Read 2 more answers
A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+
Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

C(x) = 4 + 0.10(x-70)

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

C(x) \geq 7

4 + 0.10(x - 70) \geq 7

4 + 0.10x - 7 \geq 7

0.10x \geq 10

x \geq \frac{10}{0.1}

x \geq 100

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

C(x) \leq 8

4 + 0.10(x - 70) \leq 8

4 + 0.10x - 7 \leq 8

0.10x \leq 11

x \leq \frac{11}{0.1}

x \leq 110

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0
3 years ago
Find the range of the following piecewise function.
Anna11 [10]

Given:

The piecewise function is

f(x)=\begin{cases}x+4 & \text{ if } -4\leq x

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions f(x)=x+4 and f(x)=2x-1 as linear functions.

Starting value of f(x)=x+4 is at x=-4 and end value is at x=3.

Starting value: f(-4)=-4+4=0

End value: f(3)=3+4=7

Starting value of f(x)=2x-1 is at x=3 and end value is at x=6.

Starting value: f(3)=2(3)-1=5

End value: f(6)=2(6)-1=11

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.

5 0
3 years ago
a submarine travel 184.4 meters below the water's surface. It took 23 1/2 minutes maintain a speed during a recent how far did y
cupoosta [38]

If the submarine descended 184.4 meters in 23.5 minutes, its rate of descent was ...

... (184.4 m)/(23.5 min) ≈ 7.847 m/min

The submarine descended about 7.85 meters in one minute.

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3 years ago
Which steps will verify that a parrallelogram is a rectangle
Xelga [282]

Step-by-step explanation:

"To verify that a given parallelogram is a rectangle, you can calculate the lengths of all sides, and show that both pairs of opposite sides are congruent and calculate the slopes of every side, and show that adjacent sides are perpendicular."

7 0
3 years ago
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