HELP ASAP!!!!!!

Marisol buys 3 pounds of cheese and 3 pounds of sausage for a total cost of $36. The sausage costs $2.00 less per pound than the

mamaluj [8]

Answer:

$33

Step-by-step explanation:

c = price of cheese; s = price of sausage

3c + 3s = $36

s = c - 2

3c + 3(c - 2) = 36

2c - 2 = 12

c = $ 7

s = 7 - 2 = $ 5

Therefore, price of 4 lb of cheese and 1 lb of sausage is 4c + 1s = $28 + $5 = $33

8 0

3 years ago

What are the coordinates of the Image of point M under a Reflection across the y-axis?

dexar [7]

Answer:

(C)

Step-by-step explanation:

Reflection Rule for the Y-Axis:

$(x,y) \rightarrow(-x,y)$

Using the mapping rule and Point M:

$(2,-1) \rightarrow (-2,-1)$

$\text {M' is: } (-2,-1)$

The correct option should be C.

8 0

3 years ago

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean $\mu$ and standard deviation $\sigma$ , we have these following probabilities

$Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827$

$Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545$

$Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973$

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So $\mu = 53, \sigma = 11$

So:

$Pr(53-11 \leq X \leq 53+11) = 0.6827$

$Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545$

$Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973$

-----------

$Pr(42 \leq X \leq 64) = 0.6827$

$Pr(31 \leq X \leq 75) = 0.9545$

$Pr(20 \leq X \leq 86) = 0.9973$

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have $Pr(31 \leq X \leq 75) = 0.9545 = 0.9545$ subtracted by $Pr(42 \leq X \leq 64) = 0.6827$ is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

$P = {0.9545 - 0.6827}{2} = 0.1359$

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0

4 years ago

Use addition to solve the linear system of equations. Include all of your work in your final answer.

love history [14]

We have that
<span>x - y = 4-------> multiply by -1-----> -x+y=-4-----> equation 1
x+ 2y = 4------> equation 2

add equation 1 and equation 2
-x+y=-4
x+2y=4
-----------------
0+3y=0-----> y=0
x+2y=4------> x+0=4------>x=4

the solution is the point (4,0)</span>

4 0

3 years ago

Simplify the algebraic expression: 16 - 4(3x - 5)

swat32

Step-by-step explanation:

16 - 4(3x - 5)

16 - 12x + 20

12x = 16 + 20

12x = 36

x = 36/12

x = 3

3 0

3 years ago

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