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zaharov [31]
4 years ago
7

What is the solution set for 3x>6?

Mathematics
2 answers:
zalisa [80]4 years ago
8 0
Isolate the x

divide 3 from both sides

3x/3 > 6/3

x > 6/3

x > 2 is your answer

Note: because you are not dividing by a negative number, you do not need to flip the sign

hope this helps
dalvyx [7]4 years ago
8 0
X>2 because you first divide 3 by 3, to cancel out the 3 and what you do to one side you do to the other. So you divide 6 by three which equal 2. This process is to isolate the x, so you can somewhat determine what x is. Therefore x is greater than 2, x>2
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What’s another way to write the equation (40x4)-(32x4)=32
zysi [14]

Answer:

160-128=32

Step-by-step explanation:

distribute what is in the parentheses

7 0
2 years ago
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
3 years ago
Suppose the value R(d) of d dollars in euros is given by R(d)-d The cost P(n) in dollars to purchase and ship n purses is given
S_A_V [24]

<u>Corrected Question</u>

Suppose the value R(d) of d dollars in euros is given by R(d)=\dfrac67 d. The cost in dollars to purchase and ship n purses is given by P(n)=66n+23. Write a formula for the cost, Q(n) in euros to purchase and ship n purses.

Answer:

Q(n)=\dfrac67(66n+23)

Step-by-step explanation:

The value R(d) of d dollars in euros is given by R(d)=\dfrac67 d

Therefore:

R(1)=\dfrac67

T$hat is, 1  dollars =\dfrac67$ euros

The cost P(n) in dollars to purchase and ship n purses is given by:

P(n) = 66n+23.

Therefore, the cost, Q(n) in euros to purchase and ship n purses

=\dfrac67 \cdot P(n)\\Q(n)=\dfrac67(66n+23)

8 0
3 years ago
Use the commutative property to simplify the expression 4/3 + 3/4 + 2/3
saw5 [17]

The simplified expression using  the commutative property is : \frac{6}{3} + \frac{3}{4}

<h3>Meaning of commutative property</h3>

commutative property can be defined as a mathematics attribute that is possessed by a mathematical equation, that enables the objects undergoing addition or multiplication to change position.

In conclusion, The simplified expression using  the commutative property is : \frac{6}{3} + \frac{3}{4}

<h3>Analysis</h3>

4/3 + 3/4 + 2/3 =  ( \frac{4}{3} +  \frac{2}{3} ) +  \frac{3}{4}  =   \frac{6}{3} + \frac{3}{4}

Learn more about commutative property: brainly.com/question/1528288

#SPJ1

7 0
2 years ago
EASY WORK!!plz look at the photo and yes its easy for other people but not me for people asking.
ser-zykov [4K]

Answer:

Here's a way this can help! If the graph it by two then any odd number will by by the middle, start by the origin and you'll be able to see it clearly.

8 0
3 years ago
Read 2 more answers
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