Answer:
C. 70°
Step-by-step explanation:
The inscribed angle marked 15° intercepts an arc that is double that measure, so the intercepted arc on the right is 2×15° = 30°.
The external angle marked 20° is half the difference of the intercepted arcs, so is ...
20° = (1/2)(x - 30°)
40° = x - 30° . . . . . . multiply by 2
70° = x . . . . . . . . . . . add 30°
The value of x is 70°.
Slope = 1/2 :)
rise over run (rise/run)
so... 2/4 = 1/2
hope this helps!
Answer:
15th term =29/3
16th term = 31/3
Step-by-step explanation:
Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .
First we find the 15th term
n=15
a1=1/3
d=1 - 1/3 = 2/3
Solution
1/3+(15-1)2/3
1/3+28/3
(1+28)/3
29/3
Lets find the 16th term
1/3+(16-1)2/3
1/3+30/3
(1+30)/3
31/3
Answer:
B. $39550
Step-by-step explanation:
The expression for the function is not well-formatted, find the correct format in the solution bellow
Step one:
given data
We are told that the function of the cost is
![C(t) = 0.04t^3- 0.1t^2 + 5.5t](https://tex.z-dn.net/?f=C%28t%29%20%3D%200.04t%5E3-%200.1t%5E2%20%2B%205.5t)
instantaneous rate c(t) is the value obtained when we plug in 100 for t in the function above
substituting we have
![C(t) = 0.04(100)^3- 0.1(100)^2 + 5.5(100)\\\\\C(t) = 0.04*1000000- 0.1*10000 + 5.5*100\\\\C(t) = 40000-1000+550\\\\C(t) = 39550](https://tex.z-dn.net/?f=C%28t%29%20%3D%200.04%28100%29%5E3-%200.1%28100%29%5E2%20%2B%205.5%28100%29%5C%5C%5C%5C%5CC%28t%29%20%3D%200.04%2A1000000-%200.1%2A10000%20%2B%205.5%2A100%5C%5C%5C%5CC%28t%29%20%3D%2040000-1000%2B550%5C%5C%5C%5CC%28t%29%20%3D%2039550)
$39550
Answer:
slope (m) = -50 or -50x
Step-by-step Explanation
I'm assuming that the x-axis is divided by 1 minute segments.
The slope is defined as "the change in y-coordinate" divided by "the change in x-coordinate"
Since the y value is decreasing (negative) 50 feet per minute, then it is safe to say that the slope is -50 (feet)/ 1 minute
Therefore... the slope is -50 or -50x depending on the answer the assignment is looking for