Let x = the length of the rectangle
Let w= the width
Two sections are required, hence 2w of fence required
2x+3w=500
this can be written as:
3w=1500-2x
w=(1500-2x)/3
Area=x*w
replacing w with our expression:
A=x(1500-2x)/3
A=(500x-2x^2)/3
This is a quadratic equation, if we find the axis of symmetry we will know what value of x gives maximum area:
Axis of symmetry: x=-b/2a
From our equation we get:
a=-2/3; b=1500/3
thus
x=(1500/3)/(-(-2/3))
x=750
thus the maximum area will be given by length of 750
Answer:
m = ![\frac{4L}{v^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B4L%7D%7Bv%5E%7B2%7D%20%7D)
Step-by-step explanation:
Given
L =
mv²
Multiply through by 4 to clear the fraction
4L = mv² ( divide both sides by v² )
= m
Answer:
<h2>
<em>n</em><em>=</em><em>-</em><em>7</em></h2>
<em>Sol</em><em>ution</em><em>,</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
Answer:
C
Step-by-step explanation: