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3 years ago

A fitness center offers yoga classes for $10 per class and sells yoga mats for $19.95. Linda paid

Mathematics

1 answer:

MariettaO [177]3 years ago

5 0

Answer:

12 CLASSES 10.00=120.00 PLUS 1 MAT FOR 19.95 FOR A TOTAL OF 120.00+19.95=139.95 THUS WE HAVE 12 CLASSES + 1 MAT

Step-by-step explanation:

12 CLASSES 10.00=120.00 PLUS 1 MAT FOR 19.95 FOR A TOTAL OF 120.00+19.95=139.95 THUS WE HAVE 12 CLASSES + 1 MAT

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This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

The sum of the number in each of the four rows is the same
The sum of the numbers in each of the three columns is the same
The sum of any row does not equal the sum of any column

$\bold{\underline{ Let's \: Begin}}$

According to the Second rule :-

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

According to the first rule :- 

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

From ( 1 ) we got :-

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

Subsitute (3) in ( 2 ) :-

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

We can write it as :-

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

Subsitute the value of c and e in ( 1 ):-

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

Now, 

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

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3 years ago

PLEASE HELP ME IM DESPERATE! Given the number of sides of a polygon, what is the maximum number of right angles it can have? Spe

iren2701 [21]

Answer: 5

Step-by-step explanation: Sum of Angles = 900'. 6 right angles

= 540', leaving 360', which is impossible.

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3 years ago

Subtraction and division are derived from which principal operations

melisa1 [442]

Subtraction and division are from the principal operations of PEMDAS. PEMDAS stands for parentheses, exponents, multiply and divide, add and subtract and thats it! Hope this helps and remember to mark as brainliest!

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3 years ago

If y = 100 when x = 15, which equation could you use to find the value of k?

mario62 [17]

Answer:

y+x=k

Step-by-step explanation:

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3 years ago

An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon

salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

$n=40\\\mu=\$3.82\\\sigma=\$0.33$

As n = 40 > 30, the distribution of sample mean is $\bar X\sim N(3.82,\ 0.052^{2})$ .

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

$=\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052$

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

$P(3.78$

$=P(-0.77$

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

$\bar X-\mu_{\bar x}$

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

$P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})$

$=P(Z$

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0

3 years ago