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zhannawk [14.2K]
3 years ago
14

Can someone help me with this?

Mathematics
2 answers:
grandymaker [24]3 years ago
3 0

Answer:

can u help me with sum I'll help u

Evgen [1.6K]3 years ago
3 0
1. y=(x-3)^2-12
2. y=5(x-2)^2-25

i’m going back to sleep, night
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If cos θ = .62 and if 0<θ<90 what is the approximate value of sin θ to the nearest hundredth
Deffense [45]
\cos\Theta=0.62\\\\\text{Use:}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\Theta+(0.62)^2=1\\\\\sin^2\Theta+0.3844=1\ \ \ |-0.3844\\\\\sin^2\Theta=0.6156\to\sin\Theta=\pm\sqrt{0.6156}\\\\\sin\Theta_1\approx-0.78\ \vee\ \sin\Theta\approx0.78\\\\\Theta\in(0^o;\ 90^o),\ therefore\ \sin\Theta \ \textgreater \  0\to\boxed{\sin\Theta\approx0.78}
5 0
3 years ago
John bought an iPad for $425.His total price was $450.50 when he checked out at the register.What percent sales tax did he pay?
lbvjy [14]

Answer:

6%

Step-by-step explanation:

450.5 - 425 = 25.5

25.5/425= .06

.06 times 100 = 6

3 0
3 years ago
Read 2 more answers
How do I simplify this (sinx)/(secx+1)
pochemuha

Answer:

Step-by-step explanation:

\frac{sin~x}{sec~x+1} =\frac{sin~x}{\frac{1}{cos~x}+1  } =\frac{sin~x~cos~x}{1+cos~x} \\=\frac{sin~x~cos~x}{1+cos~x} \times \frac{1-cos~x}{1-cos~x} \\=\frac{sin~x~cos~x(1-cos~x)}{1-cos^2 x} \\=\frac{sin~x~cos~x(1-cos~x)}{sin^2x} \\=\frac{cos~x(1-cos~x)}{sin~x} \\=cos ~x(csc~x-cot~x)\\or\\=cot~x(1-cos~x)

6 0
3 years ago
If ABC and GEF are congruent by the ASA criterion, which pair of angles must be congruent
Aleks04 [339]
The second one is true
4 0
3 years ago
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Pls help me if your good at math
OLEGan [10]

Answer:

First bank last function

Second blank, the middle function

Third blank, middle function

Fourth blank, first function

7 0
2 years ago
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