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3 years ago

What is the average of the following numbers .406 .407 .408 .405 .411 .406

Mathematics

1 answer:

Olin [163]3 years ago

4 0

Answer:

The average is 407.1667

Step-by-step explanation:

406+407+408+405+411+406=2,443

2,443/6=407.1667

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What +2/3=11/12 equation

Luden [163]

Answer:

1/4

Step-by-step explanation:

1st: you need to make a common denominator for 2/3 and 11/12 that would be 12, so you would keep 11/12 how it is but multiply the numerator and the denominator by 4 to get it to 12.

You would have ;

8/12+___=11/12

Then just do 11/12-8/12

so that would simplify out to 1/4

6 0

3 years ago

Read 2 more answers

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

Need help asap!!!!!!!!! :) will mark brainliest if correct!!!! <br> -4 1/3+(-3/5)

Paha777 [63]

Answer:

Step-by-step explanation:

you do the ( ) first then you do plus and get the answer

5 0

3 years ago

Which statement describes the sequence −9, −3, 3, 9, 15?

Arada [10]

C. An arithmetic sequence with common difference 6

6 0

3 years ago

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for the party,the chef makes a large cake using 325 grams of flour ,137 grams of butter ,0.53 kilogram of sugar and 0.5 kilogram

Rom4ik [11]

Answer:

1.492 kg

Step-by-step explanation: 0.5kg+0.53kg=1.03kg=1030grams

1030grams+325grams+137grams=1492 grams

1492/1000=1.492kg

<h2>PLEASE MAKE ME BRAINLIEST!!!</h2>

7 0

3 years ago