Question

Repost 8th grade 50 POINTS+BRAINLIEST: How do you graph a quadratic equation in vertex form when the equation is a perfect square? Use x² -4x+4 as an example

Answer 1

1(x-2)^2+0 is the vertex form

Answer 2

Answer: Vertex : Maximum (2, 0)

Rules:

• (x + d)² = x² + 2dx + d²    and   (x - d)² = x² - 2dx + d²

• x² + 2dx = (x + d)² - d²   and  x² - 2dx = (x - d)² - d²

Solve:

x² - 4x + 4

x² - 2(2x) + 2²

(x - 2)²

Into vertex form: a(x - h)² + k

1(x - 2)² + 0

Identify:

vertex : (h, k) = (2, 0)

Find additional things, to graph the equation:

(i) x-intercept: (2, 0)

(ii) y-intercept: (0, 4)

Graph shown: